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nikdorinn [45]
3 years ago
9

A baby weighs 115 ounces. What is the baby's weight in pounds and ounces? *Plz explain your answer*

Mathematics
2 answers:
Troyanec [42]3 years ago
5 0

Answer:

7 pounds 3 ounces

Step-by-step explanation:

There are 16 ounces in a pound. In order to convert ounces to pounds, we need to see how many 16s fit into 115 (how many full pounds can be made with 115 ounces) and add the remainder as ounces. To do this we can do long division (which gives us 7 remainder 3), or we can divide 115 by 16 (=7.1875) and convert the decimal places to ounces by multiplying 0.1875 pounds (the remainder) by 16 (as there are 16 ounces in pound) which gives us 3 ounces.

So 115 ounces is equal to 7 pounds and 3 ounces.

Hope this helped!

snow_tiger [21]3 years ago
4 0

Answer:

115 ounces = 7 pounds and 3 ounces

Step-by-step explanation:

There is 16 ounces in one pound. now divide.

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At a local seaside, a vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50. The vendor stocks a maxim
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Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of single cone ice cream and let y represent the number of double cone ice cream.

Since the vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. hence:

0 < x ≤ 70, 0 < y ≤ 45      (1)

The vendor expects to sell no more than 50 ice creams, hence:

x + y ≤ 50

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Since the vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50, hence:

Revenue = 3x + 4.5y

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John sells hamburgers ($3) and cheeseburgers ($3.50). One afternoon he sells a total of 24 burger for $79. How many of these wer
ankoles [38]

John sold 10 hamburgers and 14 cheeseburgers.

Step-by-step explanation:

Given,

Cost of one hamburger = $3

Cost of one cheeseburger = $3.50

Total burgers sold = 24

Total revenue earned = $79

Let,

Number of hamburgers sold = x

Number of cheeseburgers sold = y

According to given statement;

x+y=24   Eqn 1

3x+3.50y=79    Eqn 2

Multiplying Eqn 1 by 3

3(x+y=24)\\3x+3y=72\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(3x+3.50y)-(3x+3y)=79-72\\3x+3.50y-3x-3y=7\\0.50y=7

Dividing both sides by 0.50

\frac{0.50y}{0.50}=\frac{7}{0.50}\\y=14

Putting y=14 in Eqn 1

x+14=24\\x=24-14\\x=10

John sold 10 hamburgers and 14 cheeseburgers.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/13070361
  • brainly.com/question/13084321

#LearnwithBrainly

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Answer to 24 pls and thanks :D ik its super simple but im not very good at this and i forgot how to do it, and you guys get like
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There is no picture given for us to answer the question!
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