Answer:
W = 2747,1 [J]
Step-by-step explanation:
Chain is 64 meters long with mass 24 Kg
Then weight of the chain is p = 24 * 9.8
p = 235.2 [N] N = kg*m/s²
And by meter is 235,2 / 64 = 3.675
Total work has two component
- work to lift the 13 top meters of chain W₁
W₁ = ∫₀ᵇ F(y) dy
- work to lift last ( 64 - 13 ) meters 51 W₂
W₂ = 3.675 * 51 * 13 Kg m² /s² [J]
W₂ = 2436,53 [J]
We need to calculate W₁
W₁ = ∫¹³₀ mgy dy ⇒ W₁ = ∫¹³₀ 3,675 ydy
W₁ = 3,675* ∫¹³₀ ydy W₁ = 3,675* y²/2 |₀¹³
W₁ = 3,675* 84,5 [J]
W₁ = 310,54 [J]
And total work W
W = W₁ + W₂
W = 310,54 + 2436,53 [J]
W = 2747,1 [J]
I don’t understand u sorry ;-;
If the length is four units greater than w, then it is equal to w+4.
Answer:
(-6, -4).
Step-by-step explanation:
When you reflect coordinates over the y-axis, the x-coordinates remain the same, but the y-coordinates become their additive inverse.
The original coordinates for F are (6, -4).
The new coordinates for F would be F' (-6, -4).
