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AlexFokin [52]
3 years ago
7

Help on section A :)

Mathematics
1 answer:
N76 [4]3 years ago
5 0
Hey there!

To start, the domain of a function is the set of x values a function has, in other words, the values the function has on the x-axis.

In this function, the graph appears to have a function going on infinitely in both directions (left and right). Because of this, your domain in interval notation would be (-∞,∞) 

**Your interval notation would be in parenthesis because you cannot include negative or positive infinity as one of your values since while your graph is approaching these values, it never really reaches it.

Hope this helps and have a wonderful day! :)
You might be interested in
A new Community Center is being built in Oak Valley. The perimeter of the rectangular playing field is 382 yards. The length of
vesna_86 [32]

Answer:

The width is 50 yards and the length is 141 yards.

Step-by-step explanation:

Let's call: L the length of the field and W the width of the field.

From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:

2L + 2W = 382

Because the perimeter of a rectangle is the sum of two times the length with two times the width.

Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:

L = 3W - 9

So, replacing this last equation on the first one and solving for W, we get:

2L + 2W = 382

2(3W - 9) + 2W = 382

6W -18 +2W = 382

8W - 18 = 382

8W = 382 + 18

8W = 400

W = 400/8

W = 50

Replacing W by 50 on the following equation, we get:

L = 3W - 9

L = 3(50) - 9

L = 141

So, the width of the rectangular field is 50 yards and the length is 141 yards.

3 0
2 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
10 - 3*3 / 9 = ?<br><br> * = to the power of<br><br> / = divided by
Neporo4naja [7]

Answer:

7

Step-by-step explanation:

you need to use PEMDAS

3 x 3 x 3 = 27 divided by 9 is 3 and 10-3=7

6 0
3 years ago
AB, CD and EF are straight lines. AB is parallel to CD. Work out the size of angle y
mylen [45]

Answer: 28

Step-by-step explanation:

Simplifying

2x + 16 = 3x + -12

Reorder the terms:

16 + 2x = 3x + -12

Reorder the terms:

16 + 2x = -12 + 3x

Solving

16 + 2x = -12 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

16 + 2x + -3x = -12 + 3x + -3x

Combine like terms: 2x + -3x = -1x

16 + -1x = -12 + 3x + -3x

Combine like terms: 3x + -3x = 0

16 + -1x = -12 + 0

16 + -1x = -12

Add '-16' to each side of the equation.

16 + -16 + -1x = -12 + -16

Combine like terms: 16 + -16 = 0

0 + -1x = -12 + -16

-1x = -12 + -16

Combine like terms: -12 + -16 = -28

-1x = -28

Divide each side by '-1'.

x = 28

Simplifying

x = 28

5 0
3 years ago
Read 2 more answers
A 12-ft ladder is leaning on a building. If the base of the ladder is placed 5 feet from the building, approximately how high do
Citrus2011 [14]
A^2+b^2=c^2

5^2+b^2=12^2

25+b^2=144

b^2=144-25

b^2=119

SQUARE ROOT BOTH SIDES:

b=10.9

The answer is c.
3 0
3 years ago
Read 2 more answers
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