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3 years ago

What is the square root of 1/121

Mathematics

2 answers:

icang [17]3 years ago

8 0

Answer:

Step-by-step explanation:

example 11×11 = 121

therefore squreroots = 11

ExtremeBDS [4]3 years ago

5 0

Answer:

1/11

Step-by-step explanation:

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What are the first four terms if the sequence represented by the expression n (n-1) -4?

shepuryov [24]

We have that
<span>n (n-1) -4

for n=1
a1=1*(1-1)-4------> a1=-4

for n=2
</span>a2=2*(2-1)-4------> a2=-2

for n=3
a3=3*(3-1)-4------> a3=2

for n=4
a4=4*(4-1)-4------> a4=8

the answer is
-4,-2, 2, 8

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3 years ago

What is the value of the ratio 12 1/2 14 3/4 feet

Tanzania [10]

1.4 hope ithelped!

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3 years ago

Stephan's glass holds 450 millileters of milk. Farrah's glass holds 2/5 as much milk. How much milk does Farrah's glass hold?

inysia [295]

450*(2/5)

450 and 5 can simplify to 90

90*2 is 180

3 0

3 years ago

Read 2 more answers

10. Make q the subject of the formula 5(q + p) = 4 + 8p

vichka [17]

The formula subject to q is $\frac{4+3p}{5}$

Explanation:

The given formula is $5(q+p)=4+8 p$

We need to determine the formula subject to q.

<u>The formula subject to q:</u>

The formula subject to q can be determined by solving the formula for q.

Let us solve the formula.

Thus, we have;

$5q+5p=4+8p$

Subtracting both sides by 5p, we have;

$5q=4+3p$

Dividing both sides by 5, we get;

$q=\frac{4+3p}{5}$

Thus, the formula subject to q is $\frac{4+3p}{5}$

5 0

3 years ago

Could someone help me, please?

k0ka [10]

We can rewrite the expression under the radical as

$\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4$

then taking the fourth root, we get

$\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|$

Why the absolute value? It's for the same reason that

$\sqrt{x^2}=|x|$

since both $(-x)^2$ and $x^2$ return the same number $x^2$ , and $|x|$ captures both possibilities. From here, we have

The absolute values disappear on all but the $b$ term because all of $\dfrac32$ , $a^2$ and $c^4$ are positive, while $b^3$ could potentially be negative. So we end up with

$\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4$

3 0

3 years ago