Answer:
6
Step-by-step explanation:
6+5=11
6x2=12 12-5=7
Answer:
Fruit juice: 6 L
Lemonade: 12 L
Step-by-step explanation:
The fraction of the punch that is fruit juice is 1/(1+2) = 1/3. The amount of fruit juice Josie will need for 18 L of punch is ...
fruit juice = (1/3)(18 L) = 6 L
The remaining 18 -6 = 12 L of liquid is lemonade.
Fruit juice: 6 L
Lemonade: 12 L
Answer:
The fractional change is
% .
Step-by-step explanation:
Given as :
The original fraction = ![\dfrac{x}{y}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7By%7D)
Where numerator = x
Denominator = y
According to question
The numerator decreased by 50%
Let The new numerator = x' = x - 50% of x
I,e x' = x ( 1 -
)
Or, x' = x (
)
Or, x' =
x
or, x' =
.........A
Again
The new denominator = y' = y - 25% of y
i.e y' = y (1 -
)
Or, y' = y (
)
Or, y' = y (
)
Or, y' =
............B
So, The new fraction =
= ![\frac{\frac{x}{2}}{\frac{3 y}{4}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7Bx%7D%7B2%7D%7D%7B%5Cfrac%7B3%20y%7D%7B4%7D%7D)
Or,
= ![\frac{2 x}{3 y}](https://tex.z-dn.net/?f=%5Cfrac%7B2%20x%7D%7B3%20y%7D)
So, The fractional change =
× 100
Or, The fractional change =
× 100
Hence, The fractional change is
% . Answer
Given a binomial distribution, the probability can be approximated using a normal distribution as follows:
μ = np = 350(0.04) = 14
![\sigma=\sqrt{np(1-p)} \\ \\ =\sqrt{350(0.04)(0.96)} \\ \\ =\sqrt{13.44}=3.666](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt%7Bnp%281-p%29%7D%20%5C%5C%20%20%5C%5C%20%3D%5Csqrt%7B350%280.04%29%280.96%29%7D%20%5C%5C%20%20%5C%5C%20%3D%5Csqrt%7B13.44%7D%3D3.666)
![P(x\geq15)=1-P(x\ \textless \ 15) \\ \\ =1-P\left(z\ \textless \ \frac{15-14}{3.666/\sqrt{350}} \right)=1-P\left(z\ \textless \ \frac{1}{0.196} \right) \\ \\ =1-P(5.1032)=1-1=0](https://tex.z-dn.net/?f=P%28x%5Cgeq15%29%3D1-P%28x%5C%20%5Ctextless%20%5C%2015%29%20%5C%5C%20%20%5C%5C%20%3D1-P%5Cleft%28z%5C%20%5Ctextless%20%5C%20%20%5Cfrac%7B15-14%7D%7B3.666%2F%5Csqrt%7B350%7D%7D%20%5Cright%29%3D1-P%5Cleft%28z%5C%20%5Ctextless%20%5C%20%20%5Cfrac%7B1%7D%7B0.196%7D%20%5Cright%29%20%5C%5C%20%20%5C%5C%20%3D1-P%285.1032%29%3D1-1%3D0)
Therefore, the <span>probability that there will not be enough vegan meals is 0.</span>