Answer: If the wall is 300 meters long, the dimensions of the fence with the maximum area will be 300 × 150 = 45000 m²
Step-by-step explanation:
try combinations in a chart
190 × (600-190)/2 = 38950 = 190 × 205 increasing area
200 × (600-200)/2 = 40000 = 200 × 200
220 × (600-220)/2 = 41800 == 220 × 190
240 × (600-240)/2 = 43200 == 240 × 180
260 × (600-260)/2 = 44200 == 260 × 170
280 × (600-280)/2 = 44800 . == 280 × 160
<u>300 × (600-300)/2 = 45000 == 300 × 150</u> Maximum Area
310 × (600-310)/2 = 44950 . == 310 × 145 decreasing area
320 × (600-320)/2 = 44800 . == 320 × 140
First you do -3bk+9bk and that equals 6bk then since there are no more like terms the experssion would be simplified into 6bk+2-6b
HOPE THAT HELPED!
1.5r+15=2.25r
Combine like terms: 1.5r+15-1.5r=2.25r-1.5r
15=0.75r
Get the unknown alone: 15/.75=.75/.75r
20=r or r=20 :)
Part A. Yes, because y=f(x)=x⁵.
Part B. f(4)=2(4)+12=8+12=20.
