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2 years ago

Explain the pattern that you notice when dividing by 10,100 and 1,000

Mathematics

1 answer:

Vanyuwa [196]2 years ago

3 0

Answer:

Step-by-step explanation:

An easier way to do this type of problem, is to break it down,

10,000/1,000 is the BIG SCARY Problem, think of it like 10/1,\

1 goes into 10, 10 times,

So, what is 1,000x10?

10,000

Answer, 10

Pattern, is that is decreases by 1,000 every time and now you know

You might be interested in

Simplify (4xy-2x)+(2x^2+8x)

devlian [24]

Answer: 4xy+6x+2x^2

Step-by-step explanation:

4xy-2x+2x^2+8x

we can combine the terms that only have an x (Ax for any number A)

in this case that's -2x and 8x

-2x+8x=6x

the other things can't be combined

thus you end up with

4xy+6x+2x^2

8 0

2 years ago

4. Your older brother takes you to your uncle's house for dinner. He drives 60 minutes at a constant speed of 42 miles

Tresset [83]

Answer:

i do not know the answer to your question

3 0

3 years ago

: Find the approximate perimeter of the isosceles triangle A OPD.

AleksAgata [21]

Answer:

24.98 units

Step-by-step explanation:

The picture of the question in the attached figure

we have the coordinates

P(1,-6),D(4,3),O(7,-6)

The perimeter of triangle OPD is equal to

$P=OP+PD+OD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance OP

we have

O(7,-6),P(1,-6)

substitute in the formula

$d=\sqrt{(-6+6)^{2}+(1-7)^{2}}$

$d=\sqrt{(0)^{2}+(-6)^{2}}$

$d_O_P=6\ units$

step 2

Find the distance PD

we have

P(1,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-1)^{2}}$

$d=\sqrt{(9)^{2}+(3)^{2}}$

$d_P_D=\sqrt{90}\ units$

step 3

Find the distance OD

we have

O(7,-6),D(4,3)

substitute in the formula

$d=\sqrt{(3+6)^{2}+(4-7)^{2}}$

$d=\sqrt{(9)^{2}+(-3)^{2}}$

$d_O_D=\sqrt{90}\ units$

step 4

Find the perimeter

$P=6+\sqrt{90}+\sqrt{90}$

$P=6+9.49+9.49=24.98\ units$

4 0

3 years ago

Help pls this is 5th grade math

stich3 [128]

Answer:

1.35

2.54

3.32

4.64

5.121

6.70

8 0

3 years ago

An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile. The width of the lake is 1/5 the length o

Zina [86]

X=width of the lake
y=length of the lake.
we set out this system of equiations
x*y=9/20
x=y/5
we solve by sustitution method
(y/5)*y=9/20
y²/5=9/20
y²=(5*9)/ 20
y²=2.25
y=√2.25=1.5

x=y/5
x=1.5/5=0.3

Solution:
width of the lake=0.3 miles
lenght of the lake=1.5 miles

6 0

3 years ago