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Tcecarenko [31]
3 years ago
14

Jade's car can go 27.6 miles per gallon of gas. How many miles can she drive with 7 gallons of gas?

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer:

193.2

Step-by-step explanation:

27.6x7 27.7\\ x   7\\--------\\     19.39

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Use the information provided to write the standard form eqaution of each parabola. y=2(x+2)^2+9
gtnhenbr [62]

Answer:

y = 2 x 2 + 8 x + 17

Step-by-step explanation:


4 0
3 years ago
8th grade math
UkoKoshka [18]

Answer:

10 Milk chocolates

8 dark chocolates

6 white chocolates

24 TOTAL

\frac{10}{24} Probability that Hanissa choose a milk chocolate

Now, since she has already eaten one chocolate, then what's left is 23 chocolates.

So, since the second one should be a white chocolate and there are 6 of them, then

\frac{6}{23} - probability of choosing a white chocolate.

Then, multiply,

( \frac{10}{24} )( \frac{6}{23} )= \frac{60}{552} or \frac{5}{46}

Answer: 5/46 or 10.87%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A class sorted 45 books in 90 minutes. How long would it take to sort 120 books?
pav-90 [236]
45 \ books\ in\ 90\ minutes\\\\
120\ bookes\ in\ x\ minutes\\\\
making\ proportion\\
45-90\\120-x\\\\cross\ multiplication\\\\
45x=90*120\\\\
45x=10800\ \ \ | divide\ by\ 45\\\\x=240\\\\
It\ will\ take\ 240\ minutes.
8 0
3 years ago
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The diagonal of a square unit is x units. What is the Area of the square in terms of x
ohaa [14]
Area of square = a^2 
but
a^2 = d^2 / 2 = x^2 / 2

so area = x^2/2

answer is A. x^2 / 2 or 1/2 (x)^2

5 0
2 years ago
Read 2 more answers
Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

7 0
2 years ago
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