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Answer:
-
Step-by-step explanation:
Step 1: Add the numerator fractions.
2/5 + 3/10
Here we have to find LCD, the LCD of 5 and 10 is 10
(2*2) + 3 4 + 3
Therefore, 2/5 + 3/10 = --------------- = ------------------
10 10
= 7/10
Step 2: Now substitute 2/5 + 3/10 = 7/10 in the given fraction, we get
7/10
= ----------
-7/9
If we have fraction over fraction, we have to find the reciprocal of denominator fraction and multiply.
The reciprocal of -7/9 is -9/7
Step 3: Now multiply 13/10 and -9/7
= (7/10) x (-9/7)
= -9/10
=-9/10
The answer is -
Answer:
c) 6x + y = -52 is required equation perpendicular to the given equation.
Step-by-step explanation:
If the equation is of the form : y = mx + C.
Here m = slope of the equation.
Two equations are said to be perpendicular if the product of their respective slopes is -1.
Here, equation 1 : -x + 6y = -12
or, 6y = -12 + x
or, y = (x/6) - 2
⇒Slope of line 1 = (1/6)
Now, for equation 2 to be perpendicular:
Check for each equation:
a. x + 6y = -67 ⇒ 6y = -67 - x
or, y = (-x/6) - (67/6) ⇒Slope of line 2 = (-1/6)
but
b. x - 6y = -52 ⇒ -6y = -52 - x
or, y = (x/6) + (52/6) ⇒Slope of line 2 = (1/6)
but
c. 6x + y = -52
or, y =y = -52 - 6x ⇒Slope of line 2 = (-6)
Hence, 6x + y = -52 is required equation 2.
d. 6x - y = 52 ⇒ -y = 52 - 6x
or, y = 6x - 52 ⇒Slope of line 2 = (6)
but
Hence, 6x + y = -52 is the only required equation .