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krok68 [10]
2 years ago
9

W/4 -7 = -5 show your work

Mathematics
2 answers:
liubo4ka [24]2 years ago
7 0

Answer:

w = 15

Step-by-step explanation:

w/4 -7 = -5

w/-3 = -5

(multiply both sides by -3)

w/-3 * -3 = -5 * -3

w = 15

MaRussiya [10]2 years ago
5 0

Answer:

w = 15

Step-by-step explanation:

w/4 -7 = -5

w/-3 = - 5

w = -15

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What is the area of the rectangle? rectangle on a coordinate plane. rectangle has vertices at begin ordered pair 1 comma 3 end o
miv72 [106K]
<span>it is the letter b  because if you count closly you will see

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7 0
3 years ago
Please come answer ASAP!!!<br> 5 - n divided by 3 = 4 what is the value of n?
Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

-n = -27

Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

7 0
3 years ago
Assume each figure shown has the same orientation. Which figure is the image of square LMNP after a translation of
umka21 [38]

Figure 4 is the image of the square LMNP after the translation.

<u>Step-by-step explanation:</u>

Let us see the coordinates of the pre image LMNP as,

L (-3,1)

M(-1,1)

N(-1,-1)

P(-3,-1)

after translation of (x,y) → (x+5, y -3) the coordinates of the image obtained as,

L'(2,-2)

M'(4,-2)

N'(4,-4)

P'(2,-4) which matches the image 4.

8 0
3 years ago
Read 2 more answers
Dinosaur fossils are often dated by using an element other than carbon, like potassium-40, that has a longer half life (in this
Firlakuza [10]
The amount of substance left of a radioactive element of half life, t_{\frac{1}{2}} after a time, t, is given by:

N(t)=N_0\left( \frac{1}{2} \right)^ \frac{t}{t_{  \frac{1}{2} }}

Given that <span>potassium-40 has a half life of approximately 1.25 billion years.

The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

0.1=100\left( \frac{1}{2} \right)^ \frac{t}{1.25}} \\  \\ \Rightarrow\left( \frac{1}{2} \right)^ \frac{t}{1.25}}=0.001 \\  \\ \Rightarrow\frac{t}{1.25}\ln\left( \frac{1}{2} \right)=\ln(0.001) \\  \\ \Rightarrow \frac{t}{1.25}= \frac{\ln(0.001)}{\ln\left( \frac{1}{2} \right)} =9.966 \\  \\ t=9.966(1.25)=12.5

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is 12.5 billion years.</span>
3 0
3 years ago
SOMEONE HELP ME PLEASE
lawyer [7]

Answer:

y = 90

Step-by-step explanation:

You can use proportions to answer this question.

\frac{30}{-3} =\frac{y}{-9}

Cross multiply 30 to -9; -3 to y

-270=-3y

Isolate <em>y</em> by dividing -3 on both sides

y=90

8 0
2 years ago
Read 2 more answers
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