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bazaltina [42]
3 years ago
13

The length of a rectangular frame is represented by the expression 2x 4, and the width of the rectangular frame is represented b

y the expression 2x 10. write an equation to solve for the width of a rectangular frame that has a total area of 120 square inches. 2x2 20x − 80 = 0 4x2 28x 40 = 0 4x2 28x − 80 = 0 x2 8x 20 = 0
Mathematics
1 answer:
antoniya [11.8K]3 years ago
3 0

The equation that can be ued to solve for the width of the rectangular frame is 2x² + 14x - 40 = 0.

<h3>What is the equation that can be used to solve for the width?</h3>

A rectangle is a 2-dimensional quadrilateral with four right angles.

Area of a rectangle = length x width

(2x + 4) x (2x + 10) = 120

Expand the brackets

4x² + 20x + 8x + 40 = 120

Add similar terms

4x² +28x + 40 = 120

4x² +28x - 80 = 0

Divide through by 2

2x² + 14x - 40 = 0

To learn more about how to calculate the area of a rectangle, please check: brainly.com/question/16595449

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Step-by-step explanation:

x×k = y

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k = 12/14 = 6/7

so, the equation is

x × 6/7 = y

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y = 6x/7

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y = 6/7 x

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The number of students at a high school was decreased by 30% to 420 after the senior students graduated how many students were a
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Answer:

Step-by-step explanation:

s(1-30/100)=420

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3 years ago
An angle measures 5π/12 radians.<br><br><br>What is this angle’s measure, in degrees?
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Step-by-step explanation:

\because \pi^{c}  = 180 \degree \\  \\  \therefore \:  \frac{5\pi^{c}}{12}  =  \frac{5 \times 180 \degree}{12}  = 5 \times 15 = 75 \degree

7 0
4 years ago
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17in.

Step-by-step explanation:

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3 years ago
Eliminate the x and y
sp2606 [1]

Step-by-step explanation:

Eliminate the x:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by (-3)}\\\\\left\{\begin{array}{ccc}-3(x-2y)=(-3)(6)\\3x+y=4\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-3x+6y=-18\\3x+y=4\end{array}\right}\\.\qquad\qquad7y=-14\\.\qquad\qquad y=-2

Eliminate the y:

\left\{\begin{array}{ccc}x-2y=6\\3x+y=4\end{array}\right\\\\\text{Multiply by 2}\\\\\left\{\begin{array}{ccc}x-2y=6\\2(3x+y)=(2)(4)\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}x-2y=6\\6x+2y=8\end{array}\right}\\\\.\qquad7x=14\\.\qquad x=2

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3 years ago
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