Answer:
t=6
Step-by-step explanation:
I think that it's 3.8 because the triangles are congruent but I might be wrong.
Answer:
![\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-55%5C%5C3%2639%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
![\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-15%5C%5C3%2615%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-40%5C%5C0%2624%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2B32%26-15%2B%28-40%29%5C%5C3%2B0%2615%2B24%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D32%26-55%5C%5C3%2639%5Cend%7Barray%7D%5Cright%5D)
Answer:
126
Step-by-step explanation:
14*9=126
<u>Answer:
</u>
The standard form of
is 20,00,0000
<u>Solution:
</u>
Given that
---- eqn 1
To write
in standard form,
We know that
.So
becomes
.
Now eqn 1 becomes,
----- eqn 2
We know that
, so 
Now eqn 2 becomes,

---- eqn 3
Expanding
:
Here 10 is the base term and 7 is the exponent value. So base term 10 is multiplied by itself 7 times.

Now eqn 3 becomes,

= 20,00,0000
Hence the standard form of
is 20,00,0000