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Snowcat [4.5K]
2 years ago
7

Given matrices A and B shown below, find (3)A+(8)B.

Mathematics
1 answer:
Tasya [4]2 years ago
5 0

Answer:

\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

Step-by-step explanation:

\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

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Answer:

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Step-by-step explanation:

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3 years ago
How do u solve 4(3x-1)=9-x
Nastasia [14]

Answer:

x = 1

Step-by-step explanation:

Well the first step is to apply the distributive property:

4(3x - 1) is equal to (12x - 4). You DISTRIBUTE a '4' to what is inside the parentheses.

And btw, to make it easier, you can make 9 - x so that x is first. For example, (-x + 9). They're both the same thing, just written differently.

Your new equation is 12x - 4 = -x + 9. You want to now solve the equation.

Add the (-x) to both sides. It cancels out on the right side and you add it to 12x on the left side.

[If there's no number in front of a variable, you can always just put 1 in order to make it easier]

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5 0
3 years ago
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alexandr1967 [171]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Very confusing i know
777dan777 [17]

Answer:

  • (x + 10)² + (y + 4)² = 232

Step-by-step explanation:

<h3>Given </h3>
  • Center = (-10, -4)
  • Point on circle = (4, 2)
<h3>To find </h3>
  • The equation of circle
<h3>Solution</h3>

<u>Remember the standard equation of circle:</u>

  • (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius

<u>We have</u>

  • h = -10, k = -4

Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.

<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>

  • r² = (-10 - 4)² + (-4 - 2)²
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  • r² = 232

<u>So the equation is:</u>

  • (x + 10)² + (y + 4)² = 232
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Answer:

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Step-by-step explanation:

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3 years ago
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