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Snowcat [4.5K]
2 years ago
7

Given matrices A and B shown below, find (3)A+(8)B.

Mathematics
1 answer:
Tasya [4]2 years ago
5 0

Answer:

\left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

Step-by-step explanation:

\left[\begin{array}{ccc}0&-15\\3&15\end{array}\right] +\left[\begin{array}{ccc}32&-40\\0&24\end{array}\right] =\left[\begin{array}{ccc}0+32&-15+(-40)\\3+0&15+24\end{array}\right] = \left[\begin{array}{ccc}32&-55\\3&39\end{array}\right]

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MariettaO [177]

Answer:

AQ = 20 units

Step-by-step explanation:

Comparing triangle AQR to ABC,

\frac{AQ}{AB} = \frac{QR}{BC}

\frac{4p}{8p} = \frac{2p + 3}{6p-4}

cross multiply and make p the subject of formula, we have:

8p (2p+3) = 4p(6p-4)

16p^{2} + 24p = 24p^{2} - 16p

24p + 16p = 24p^{2} - 16p^{2}

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divide through by 8p,

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Therefore, AQ = 4p

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3 years ago
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Let's just choose "x" as our variable for the length of a side of the triangle.

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Answer:

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Step-by-step explanation:

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Answer:

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