1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vagabundo [1.1K]
2 years ago
8

2x - 5 = 23(19) - 56 4x2 + 2(14) = 102/2

Mathematics
1 answer:
ra1l [238]2 years ago
7 0

Answer:

2x-5=23(19)-56\\x=193

-------------------------------

4x(2)+2(14)=\frac{102}{2}\\x=\frac{23}{8}

Step-by-step explanation:

You might be interested in
Find y.<br> 30<br> 20 <br> Need help asap
Neporo4naja [7]

Answer:

y = 10

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = \frac{1}{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{y}{20} = \frac{1}{2} ( cross- multiply )

2y = 20 ( divide both sides by 2 )

y = 10

7 0
2 years ago
. i will give brainliest.A man is 26 years older than his son. He is also 8 years older than three times his son’sage.
Shkiper50 [21]

Step-by-step explanation:

Let the son's age be x and man be y

y=26+x

y=8+3x

x=9

Son's age is 9

6 0
3 years ago
Read 2 more answers
write an equation of the line passing through the point (6,3) that is perpendicular to the line 5x - 6y = 10​
Jlenok [28]

Answer:

5x-6y-12=0

Step-by-step explanation:

...make y the subject y=-6/5x +2

...use the coefficient of x as the gradient,m=-6/5

...for a perpendicular line,find the negative reciprocal of the gradient,5/6

...sub into the eqn y= -1/m(x-a)+b

3 0
3 years ago
Find the value of x <br><br> a. 7.5<br> b. 6<br> c. 10<br> d. 8
Radda [10]
B.6 because the length is equal to the length of the other 6
7 0
3 years ago
. Two bicyclists, Sarah and Emily, depart from the same location. Sarah heads N55°E at an average speed of 6 km/hr. Emily heads
Liula [17]

Answer:

The distance between them after 30 minutes is 6.5 km.

Step-by-step explanation:

Speed = \frac{distance}{time}

Sarah's speed = 6 km/hr = 1.6667 m/s

Emily's speed = 10 km/hr = 2.7778 m/s

The measure of angle between their bearings = 105^{o}

After 30 minutes (1800 seconds);

distance = speed x time

Sarah would have covered a distance = 1.6667 x 1800

                               = 3000 m

                               = 3 km

Emily would have covered a distance = 2.7778 x 1800

                               = 5000 m

                               = 5 km

The distance between them, a, can be determined by applying the cosine rule;

a^{2} = b^{2} + c^{2} - 2bcCos A

   = 5000^{2} + 3000^{2} -2(5000 x 3000) Cos 105

   = 5000^{2} + 3000^{2} -2(5000 x 3000) x (-0.2588)

   = 2.5 x 10^{7} + 9 x 10^{6} + 7764000

   = 41764000

a = \sqrt{41764000}

  = 6462.5073

a = 6462.5 m

The distance between them after 30 minutes is 6.5 km.

4 0
2 years ago
Other questions:
  • How to solve the different ways to find answer to 12 - 3?
    6·1 answer
  • Alice had pounds of flour at the beginning of the week. at the end of the week, she had pounds. how much has she used?
    7·1 answer
  • Answe these two, please show your work
    8·2 answers
  • A road crew is widening a street that is 24 m wide. Their scale drawing says the new street has to be 125% of the width of the o
    8·2 answers
  • Let the sequence {an} be defined so that a1 = 1 and each succeeding term is found by adding 3 to the one before it. Find the for
    13·1 answer
  • the numbers below represent 10 trials of a simulation 2632, 1365,9367,2056, 0026, 6564, 1434, 8045, 4781, 8681 the numbers 0-7 r
    15·1 answer
  • What is the range of values of x for a triangle's third side given side measures of 8 and 15 for the other two sides?
    5·2 answers
  • PLEASE I NEED HELP THIS NEEDS TO GET DONE SOON AND IM STUCK):
    14·1 answer
  • pls help me with this i’ve been stuck on it for a while but i did it on paper and it doesn’t look right
    8·1 answer
  • 20POINTS <br> help me please
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!