Answer:
Step-by-step explanation:
Your answer 17 is correct
Answer:
Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Answer
A is the symbol for parallel lines AB and XY.
Explanation
B shows that line segment AB and XY are parallel, because there are no arrows, and line segments do not extend forever.
C shows that ray AB and XY are parallel, because there is one arrow, and rays only extend on one point.
Only A shows that line AB and XY are parallel. Lines extend forever, the A shows that AB and XY are parallel, since there are arrows in both directions above AB and XY.
Answer:
4
Step-by-step explanation:
To find the square of a number, you multiply it by itself. This means √4 * √4 gives the answer. √4 can be simplified to 2 because 2^2 is 4. So, 2 *2 gives the answer, which is 4.
