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Zolol [24]
3 years ago
7

Write each expression as a cube 27x^3

Mathematics
2 answers:
horsena [70]3 years ago
4 0

Answer:

How though?

Step-by-step explanation:

krok68 [10]3 years ago
4 0
(3x)^3 I think this is what you mean!!
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What is square root in simplified form? What is in simplified form?
Anon25 [30]

Answer:

Step-by-step explanation:

Let as us 45 as the number we should use to get the square root in the simplest form

And then 144

The square root of a number in is simplest form means to get the number inside the radical as low as possible

8 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
alisha [4.7K]

Answer:

The first answer

Step-by-step explanation:

If you take 14 divided by 9 and then take 14 divided by the answer you got you get the answer 9.

-Hope this helps!-

-Please mark as brainliest!-

-Good luck!-

7 0
3 years ago
What’s the answer????
Ganezh [65]
4a and 14a can be combined with 3a! Hope this helped
5 0
3 years ago
Find the volume of the solid generated when R​ (shaded region) is revolved about the given line. x=6−3sec y​, x=6​, y= π 3​, and
Dmitrij [34]

Answer:

V=9\pi\sqrt{3}

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

V=\int\limits^b_a {\pi r^{2}} \, dy

where:

r=6-(6-3 sec(y))

r=3 sec(y)

a=0

b=\frac{\pi}{3}

so the volume becomes:

V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy

This can be simplified to:

V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy

and the integral can be rewritten like this:

V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy

which is a standard integral so we solve it to:

V=9\pi[tan y]\limits^\frac{\pi}{3}_0

so we get:

V=9\pi[tan \frac{\pi}{3} - tan 0]

which yields:

V=9\pi\sqrt{3}]

6 0
4 years ago
Four friends each took different path walking from the lunchroom to the gymnasium
xxMikexx [17]

finish the question..............

6 0
2 years ago
Read 2 more answers
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