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Zolol [24]
2 years ago
7

Write each expression as a cube 27x^3

Mathematics
2 answers:
horsena [70]2 years ago
4 0

Answer:

How though?

Step-by-step explanation:

krok68 [10]2 years ago
4 0
(3x)^3 I think this is what you mean!!
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–3(x – 14) + 9x = 6x + 42
sesenic [268]

Answer:

All real numbers

0 = 0

Step-by-step explanation:

Hope i'm right

Solving this equation results in the statement 0 = 0. Because this is a true statement, the equation has infinitely many solutions.

3 0
2 years ago
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Caleb and 2 friends are sharing 1/2 quart of milk equally. What fraction of a quart of milk does each of the 3 friends get?
marissa [1.9K]
They each get 1/6 part of milk
5 0
3 years ago
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Divide 33 photoes into 2 groups so the ratio is 4 to 7
natali 33 [55]

Answer:

12:21

Step-by-step explanation:

4 + 7 = 11

33/11 = 3

3x4=12 & 3x7=21

Therefore, ratio is, 12:21

3 0
3 years ago
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What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
NEED HELP ASAP!!!
lys-0071 [83]

Answer:

3 and 4: B

Step-by-step explanation:

As per the property of traversal lines, when two parallel lines are cut by traversal then the corresponding angles formed are equal.

In given case ∠6 is corresponding angle of ∠8 and ∠8 is corresponding to ∠18.

Hence option B is correct for 3 and statements!

If lines are ||, corresponding angles are equal.

8 0
3 years ago
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