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Reptile [31]
3 years ago
14

62865 x 17 using the standard algorithm

Mathematics
1 answer:
LenKa [72]3 years ago
3 0

The standard algorithm of multiplication is the use of partial products to calculate the products of numbers.

The product of 62865 and 17 using standard algorithm is 1068705

Given

62865 \times 17

Using the standard algorithm, the product will be rewritten as follows:

\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7\end{array}\right

<u>Multiply 7 by 5;</u>

<em>The result is 35; write down 5; carry 3</em>

\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & & & &5\end{array}\right

<u>Multiply 7 by 6;</u>

<em>The result is 42; add 42 to the previous carry (i.e. 3)</em>

<em>The result is 45; write down 5; carry 4</em>

\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & & &5 &5\end{array}\right

<u>Multiply 7 by 8;</u>

<em>The result is 56; add 56 to the previous carry (i.e. 4)</em>

<em>The result is 60; write down 0; carry 6</em>

<em />\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& & &0 &5 &5\end{array}\right

                   

<u>Multiply 7 by 2;</u>

<em>The result is 14; add 14 to the previous carry (i.e. 6)</em>

<em>The result is 20; write down 0; carry 2</em>

<em />\left\begin{array}{ccccc}6&2&8&6&5\\\times& & &1&7& &0 &0 &5 &5\end{array}\right

                   

<u>Multiply 7 by 6;</u>

<em>The result is 42; add 42 to the previous carry (i.e. 2)</em>

<em>The result is 44; write down 44; because we have reached the first digit</em>

<em />\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\end{array}\right

<u>Multiply 1 by 5;</u>

<em>The result is 5; write down 5</em>

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&&&5\end{array}\right

<u>Multiply 1 by 6;</u>

<em>The result is 6; write down 6</em>

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&&6&5\end{array}\right

<u>Multiply 1 by 8;</u>

<em>The result is 8; write down 8</em>

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&&8&6&5\end{array}\right

<u>Multiply 1 by 2;</u>

<em>The result is 2; write down 2</em>

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\&2&8&6&5\end{array}\right

<u>Multiply 1 by 6;</u>

<em>The result is 6; write down 6</em>

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\6&2&8&6&5\end{array}\right

<u>Add the calculated results;</u>

<em>i.e. 440055 and 628650</em>

So, we have:

\left\begin{array}{cccccc}&6&2&8&6&5\\\times& & & &1&7\\ 4&4&0 &0 &5 &5\\6&2&8&6&5\\10&6&8&7&0&5\end{array}\right

Hence:

62865 \times 17 =1068705

Learn more about standard algorithm at:

brainly.com/question/11380840

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