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8_murik_8 [283]
3 years ago
8

PLiss i really need help pliss, plisss

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0

Step-by-step explanation:

I tried. if I got this wrong I might need to go back to kindergarten

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What does domain mean
Citrus2011 [14]
Domain means the input of x-values
example: (4,3)                         (2,1)
                 ↑                              ↑
              Domain                    Domain
5 0
3 years ago
Find a focus for this conic section. 9x^2+25y^2-200y+175=0
Katena32 [7]
First of all we have to figure out what type of a conic this is.  We know it's not a parabola because it has both an x-squared term and a y-squared term.  There's a plus sign separating the squared terms so we know it also cannot be a hyperbola.  It's either a circle or an ellipse.  If this was simply a circle, though, we would not have leading coefficients on the squared terms (other than a 1).  Circles have a standard form of (x-h)^2+(y-k)^2=r^2.  That makes this an ellipse. Let's group together the x terms and the y terms and move the constant over and complete the squares to see what we have.  9x^2+25y^2-200y=-175.  Since there's only 1 term with the x squared expression we cannot complete the square on the x's but we can on the y terms.  First, though, the rule for completing the square is that the leading coefficient has to be a 1 and ours is a 25, so let's factor it out. 9x^2+25(y^2-8y)=-175.  To complete the square we take half the linear term, square it, and add it to both sides.  Our linear term is 8.  Half of 8 is 4, and 4 squared is 16. So we add a 16 into the parenthesis, BUT we cannot disregard that 26 sitting out front there.  It refuses to be ignored.  It is still considered a multiplier.  So what we are really adding on to the right side is 25*16 which is 400.  9x^2+25(y^2-8y+16)=-175+400 which simplifies to 9x^2+25(y^2-8y+16)=225.  The standard form of an ellipse is \frac{(x-h)^2}{a^2}+ \frac{(y-k)^2}{b^2} =1 if its horizontal axis is the transverse axis, or \frac{(x-h)^2}{b^2}+ \frac{(y-k)^2}{a^2}=1 if its vertical axis is the transverse axis.  Notice that the a and b moved as the difference between the 2 equations.  A is always the larger value and dictates which ellipse you have, horizontal or vertical.  Our equation has a 225 on the right, so we will divide both sides by 225 to get that much-needed 1 on the right: \frac{x^2}{25}+ \frac{(y-4)^2}{9}=1.  Because 25 is larger than 9, this is a horizontal ellipse, our a value is the square root of 25 which is 5, and our b value is the square root of 9 which is 3.  The center is (0, 4).  You want the focus and now we can find it.  The formula for the focus is c^2=a^2-b^2 where c is the distance from the center to the focus.  We have an a and a b to find c: c^2=25-9, which gives us that c=4.  The focus is 4 units from the center and always lies on the transverse axis.  It shares a y value with the center and moves from the x-coordinate of the center the value of c.  Our center is (0, 4) so our y value of the focus is 4; our x coordinate of the center is 0, so the x value of the focus is 4.  The coordinates of the focus are (4, 4).
8 0
3 years ago
OK it has 5 g Of sugar per serving. A banana has 15 g of sugar per serving.
myrzilka [38]

1/3 banana hgfdsedcrtvfybgunhimjnyhtbgvfdcvfbgnhmij,omhnbvdcrmjytgvg

4 0
3 years ago
The account
Orlov [11]

Answer:

850- 475= 375 increase over 2 months.

375 ÷2= $187.50

4 0
3 years ago
The ratio of petunias to geraniums in the greenhouse was 15 to 2. Combined there was 1020. How many geraniums were in the greenh
Mrac [35]

in short, we simply split the total amount by the given ratio, so we'll split or divide 1020 by (15 + 2) and then distribute accordingly.

\bf \cfrac{petunias}{geraniums}\qquad 15:2\qquad \cfrac{15}{2}~\hspace{7em}\cfrac{15\cdot \frac{1020}{15+2}}{2\cdot \frac{1020}{15+2}}\implies \cfrac{15\cdot \frac{1020}{17}}{2\cdot \frac{1020}{17}} \\\\\\ \cfrac{15\cdot 60}{2\cdot 60}\implies \cfrac{900}{120}\implies \stackrel{petunias}{900}~~:~~\stackrel{geraniums}{120}

5 0
3 years ago
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