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dybincka [34]
3 years ago
5

Look at image worth 20 pointd help!!

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

y=-\frac{9}{7}x-2

Step-by-step explanation:

Here, we have to convert the equation to slope-intercept form so we can find the perpendicular slope:

7x-9y=-5

-9y=-5-7x

y=-\frac{5}{9}+\frac{7}{9}x

y=\frac{7}{9}x-\frac{5}{9}

Since our slope is m=\frac{7}{9}, then that means the slope perpendicular to it is m=-\frac{9}{7}.

Now we find our new y-intercept so that the line will pass through the point (-7,7):

y=mx+b

y=-\frac{9}{7}+b

7=-\frac{9}{7}(-7)+b

7=9+b

-2=b

Therefore, the equation of the new line is y=-\frac{9}{7}x-2

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What is a linear equation that contains these points?​
shepuryov [24]

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C

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7 0
3 years ago
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Harman [31]
Lila did it correctly. The answer is 324

Following PEMDAS, we first focus on the parenthesis. So we simplify 9-3 to get 6

So we go from 
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The next step is applying exponents. In this case, squaring the terms, so we go from
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18*16+36
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That confirms that Lila is correct

----------------------

The error that Rob made is that he computed 18*4^2+9^2-3^2 but it is NOT correct. Saying (x-y)^2 = x^2-y^2 isn't a true equation for all x and y. Again you have to simplify what is in the parenthesis first, and then you can square it. Or you must use the FOIL rule to expand out (9-3)^2


7 0
3 years ago
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