Answer:
f'(1)=150ln(1.5)
Step-by-step explanation:
I'm not sure why you would need a table since the limit definition of a derivative (from what I'm remembering) gives you the exact formula anyway... so hopefully this at least helps point you in the right direction.
My work is in the attachment but I do want to address the elephant on the blackboard real quick.
You'll see that I got to the point where I isolated the h's and just stated the limit equaled the natural log of something out of nowhere. This is because, as far as I know, the way to show that is true is through the use of limits going to infinity. And I'm assuming that you haven't even begun to talk about infinite limits yet, so I'm gonna ask you to just trust that that is true. (Also the proof is a little long and could be a question on it's own tbh. There are actually other methods to take this derivative but they involve knowing other derivatives and that kinda spoils a question of this caliber.)
Answer: The mass of the object is 10 kg
Step-by-step explanation:
According to Newton's second law of motion, the force 
applied to an object with mass 
is directly proportional to its acceleration 
:
(1)
If we isolate :
(2) This means the acceleration of the object varies inversely with its mass
Now, we are given the following data to calculate a constant force using (1):
(3)
(4)
(5)
If we apply this same force calulated in (4) in another object with an acceleration of 
, its mass 
will be:
(6)
(7)
Finding :
This is the mass of the object
Answer:
The initial height of an object above ground before being launched straight up in the air
Step-by-step explanation:
we have
we know that
The number 72 represent the y-intercept of the function
The y-intercept is the value of y when the value of x is equal to zero
In this problem
The value of h when the value of t is zero
Therefore
The initial height of an object above ground before being launched straight up in the air
No puedo ayudar srry primo
The range of y=e^x+1 is y>1.
