Question

What are the solutions to x^2-5x+3=0?

Answer 1

Answer:

Step-by-step explanation:

You need to use the quadratic equation

x =  $\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}$

Givens

• a = 1
• b = - 5
• c = 3

x = $\frac{5 +/- \sqrt{5^2 - 4a*1*3} }{2}$

x =( 5 +/- sqrt(25 - 12) ) / 2

x = (5 +/- sqrt(13) )/2

x = (5 + sqrt(13) / 2

x = 4.303  rounded

x = (5 - sqrt(13) ) /2

x = .6972