17. A disposable camera costs $6.95. A party planner wants to buy 100 cameras for an

Mathematics

1 answer:

natima [27]3 years ago

5 0

Answer:

$695

Step-by-step explanation:

So if each camera costs $6.95 snd he wants 100 you would multiply by 100. And that would be 6.95×100=695 and a good trick I've learnt is that you just move the numbers 1 column to the left for each zero so if it was 10 you'd move all the numbers 1 column to the left. It is abit hard to explain but you're answer is there just thought that'd help in future.

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Round to the nearest hundredth. I need to be walked through the steps :)

Mamont248 [21]

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6 0

3 years ago

Read 2 more answers

Helppp lol which system of linear equations is represented by the graph?

kondaur [170]

Answer:

y ≥ x - 2, and x + 2y < 4 ; Option C

Step-by-step explanation:

Consider the y - intercept and slope of 1 of these given lines,

$y - intercept = ( 0, - 2 ) / - 2\\slope = 1 / 1 = 1$

From this we can formulate the equation of 1 line;

$Take Equation In the Form - y = ax + b, a - slope, and , b - y intercept,\\y = ax + b, a = 1, b = - 2,\\Equation of Line 1 - y = x - 2$

Now consider the y - intercept and slope of the remaining line;

$y - intercept = ( 0, 2 ) / 2\\slope = 1 / - 2 = - \frac{ 1 }{ 2 }$

This creates a line with the equation as such;

$Take Equation In the Form - y = ax + b, a - slope, and , b - y intercept,\\y = ax + b, a = - 1 / 2, b = 2,\\Equation of Line 1 - y = - \frac{ 1 }{ 2 } x + 2, x + 2y = 4$

From this we see that the solution of the system is such;

Solution ; y ≥ x - 2, and x + 2y < 4 ; Option C

6 0

3 years ago

How many eighth-size parts do you need to model 3/4? explain

Ostrovityanka [42]

The way I understand this question is: "how many of one eights (1/8) can fit into 3/4 - so mathematically we would write: 3/4 divided by 1/8. Dividing by a fraction is multiplying by its inverse, so we have 3/4 multiplied by 8, which is 3*8/4, we simplify by dividing 8 and 4 by 4: 6/1, that is 6 - the answer is 6!Hope this helps. Let me know if you need additional help!

8 0

3 years ago

If you flip three fair coins, what is the probability that you'll get a tail on the first flip, a head on the secand flip. And a

DENIUS [597]

Answer:

Probability of getting {THT} is 0.125

Step-by-step explanation:

Since 3 fair coins are tossed we can get the sample space for the experiment.

Sample space of the experiment = {HHH, HHT, HTT, HTH, TTH, THH, THT, TTT}

As per question ,

Getting Tail , Head, Tail is a success so all other events other than {THT} is a failure.

Therefore probability of getting {THT} = $\frac{1}{8}$ = 0.125