Given:
A figure of combination of hemisphere, cylinder and cone.
Radius of hemisphere, cylinder and cone = 6 units.
Height of cylinder = 12 units
Slant height of cone = 10 units.
To find:
The volume of the given figure.
Solution:
Volume of hemisphere is:

Where, r is the radius of the hemisphere.



Volume of cylinder is:

Where, r is the radius of the cylinder and h is the height of the cylinder.



We know that,
[Pythagoras theorem]
Where, l is length, r is the radius and h is the height of the cone.

Volume of cone is:

Where, r is the radius of the cone and h is the height of the cone.



Now, the volume of the combined figure is:



Therefore, the volume of the given figure is 2110.08 cubic units.
Answer:
$64
Step-by-step explanation:
Since there were 4 of them and the coupons were $10 off, they saved a total of $40
To find how much they would have spent without the coupons, add 40 to 216:
216 + 40
= 256
To find the normal cost of one ticket, divide this by 4:
256/4
= 64
So, the price of one concert ticket without the coupon is $64
Answer:
d = 1.5
Step-by-step explanation:
yes
First solve the quadratic as you would an equation, so you will get two real zeroes p and q so that (x-p)(x-q)=0 is another way of expressing the quadratic. All quadratics can be represented graphically by a parabola, which could be inverted. When the x² coefficient is negative it’s inverted. If the coefficient of x² isn’t 1 or -1 divide the whole quadratic by the coefficient so that it takes the form x²+ax+b, where a and b are real fractions. The curve between the zeroes will be totally below the x axis for an upright parabola, and totally above for an inverted parabola. This fact is used for inequalities. An inequality will be <, ≤, > or ≥. This makes it easy to solve the inequality. If the position of the curve between the zeroes is below the axis then outside this interval it will be above, and vice versa. So we’ve defined three zones. x
q, and p
Answer:
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Step-by-step explanation:

- Convert the mixed fractions into improper fractions.







