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3 years ago

Can someone help me answer this?

Mathematics

2 answers:

julia-pushkina [17]3 years ago

6 0

Answer:

angle JCL

Step-by-step explanation:

complementary angles together equal to 90, which are L-shaped and have squares in the corners instead of circles.

Masja [62]3 years ago

3 0

Your answer is angle JCL.

Angle JCL+Angle LCT = 90°

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Four horses ran in a race

irina [24]

Answer:

Dee won

Step-by-step explanation:

Using < to mean "finished ahead of ", we are given ...

B = 3

D < B

D < C

A < C

D < A

Dee finished ahead of Air, Bart, and Caper, so Dee won the race.

_____

The order of finish must be D, A, B, C.

3 0

3 years ago

Two sides of a triangle have the following measures. Find the range of possible measures for the third side.

strojnjashka [21]

Answer:

1 and 15

Step-by-step explanation:

8-7=1

8+7=15

3 0

2 years ago

A. complete the table.

kkurt [141]

Sorry if this wrong but i got 8.

3 0

3 years ago

I need help ASAP!!

chubhunter [2.5K]

Aloha!
The answer would be 2!
Angela would have double if he gave her one.
And they could also be equal!

I hope this helps!!!
Adios!:))

7 0

3 years ago

Suppose we are sending a digital signal which is a string of 0s and 1s of length five. (Example stringsare 00101, 11000, 10101 a

masha68 [24]

Answer:

0.7738 = 77.38% probability that an incorrect message is received.

Step-by-step explanation:

For each bit, there are only two possible outcomes. Either it is corrupted, or it is not. The probability of a bit being corrupted is independent of any other bit. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% probability a bit is sent incorrectly:

This means that $p = 0.05$

Message of length 5

This means that $n = 5$

What is the probability that an incorrect message is received?

This is the probability of at least one incorrect bit, which is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.05)^{0}.(0.95)^{5} = 0.7738$

0.7738 = 77.38% probability that an incorrect message is received.

4 0

3 years ago