Combinatorial Enumeration. That whole class was a rollercoaster ride of mind-blowing generating functions to prove crazy things. The exam had ridiculous questions like 'count the number of cactus trees with n vertices such that etc etc etc' and you'd do three pages of terrible terrible sums and algebra. Then your final answer would be something beautiful like n/2 and you'd breath a sigh of relief and thank the math gods.
I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:
Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.
So, the answer is 34.
Answer:
Convert the mixed numbers to improper fractions, then find the LCD and combine.
Exact Form:
58
/15
Decimal Form:
3.8
6
Mixed Number Form:
3 13
/15
Step-by-step explanation:
Area of trapezoid : (Base 1 + base 2) x h x 1/2
Let's solve!
( 2+6) x 5 X1/2
= 40x1/2
=20
20 in squared is the area!
Remember when you see those two signs next to each other its “kao” which is keep add opposite so for b its 6-(-3) but you do keep add opposite so now it’s 6+3=9. for c it’s -2-(-5) and we still do kao which now it’s -2+5 different signs you subtract so now it’s 3 we always keep the sign of the higher variable and 5 is positive so the answer is positive.
