Answer:
Length of Shorter leg = 27 feet
Length of Longer leg = 36 feet
Length of Hypotenuse = 45 feet
Step-by-step explanation:
Given:
Let,
Length of Shorter leg = x,
According to the given condition we have
∴ Length of Longer leg = x + 9 feet
∴ Length of Hypotenuse = 2x - 9 feet
To Find:
Length of Shorter leg = ?
Solution:
Now In Right Angle Triangle, By Pythagoras theorem we have

substituting the given values we get

By using Identity (A ± B)² = A² ± 2AB +B² we get

Substituting x=27 we get
∴ Length of Longer leg = x + 9 =27 +9 = 36 feet
∴ Length of Hypotenuse = 2x - 9 = 2×27 -9 = 45 feet
Answer:
a perfect square because 17 x 17 = 289
It's not a perfect cube
Step-by-step explanation:
Answer: If a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.
If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.
Step-by-step explanation:
So if a number is rational, it can be represented as a simple fraction, it can be written as a terminating decimal, and a repeating decimal.
If a number is irrational, it cannot be represented as a simple fraction, it cannot be written as a terminating decimal, and not as a repeating decimal. It never ends, never repeats, just like the constant pi.
I believe the answer is 4 because 6m/29= 20.6897 and so then you do 20.6897 x 3= 62.0691. So 3 is too small so do 20.6897x 4= <span>82.7588. 82 >78 so the answer is that you need 4 boards.
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x+2 > 10 solves to x > 8 after we subtract 2 from both sides
So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.
Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.
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Summarizing everything, we can say...
5 is not in set A. True
5 is in set B. False
6 is in set A. False
6 is not in set B. False
8 is not in set A. True
8 is in set B. True
9 is in set A. True
9 is not in set B. False