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3 years ago

What is the length of a line segment with endpoints of 19 and –39

Mathematics

2 answers:

Vlad [161]3 years ago

6 0

19-(-39)
19+39=58
is solution as
the two end points are 19 and -39 we should subtract then we get the distance between

gtnhenbr [62]3 years ago

5 0

Answer: 58 units

Step-by-step explanation: In this problem, the given numbers 19 and -39 represent the coordinates of the endpoints of a segment and we are asked to find the length of the segment.

To find the length of a segment, we take the greater endpoint coordinate minus the lesser endpoint coordinate.

In this case, the greater endpoint coordinate is 19 and the lesser endpoint coordinate is -39.

So, we have 19 - (-39) which can also be thought of as 19 + 39 which equals 58.

Therefore, the length of this segment is 58 units.

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What are the solutions to the quadratic equation (5y + 6)^2 = 24?

DiKsa [7]

Step-by-step explanation:

(5y+6)^2=24

i.e, 25y^2+60y+36=24

i.e, 25y^2+60y+12=0

i.e, using rule of quadratic equns

y= {-60±√3600-(4×25×12)}/2×25

i.e,y= (-60±√2400)/50

i.e,y= -1.2 ± 0.4√6

✌️:)

4 0

3 years ago

Read 2 more answers

Matthew is going to drive from Salt Lake City, Utah, to Las Vegas, Nevada. His car travels a consistent

Eddi Din [679]

Answer: 14 gallons of gasoline.

Step-by-step explanation:

given data:

25(x + 3) = 424

where x is the number of gallon of gasoline needed to purchase.

Solution.

25(x + 3) = 424

first we open the bracket

25x + 75 = 424

collect like terms

25x = 424 – 75

25x = 349

divide both sides by 25

25x/25 = 349/25

x = 13.96

x = 14

mathew needs to get 14 gallons of gasoline.

5 0

4 years ago

You are working as a clinical chemist in charge of testing of the blood samples. you are required to fix a sodium chloride solut

Dafna11 [192]

$\bf \cfrac{sodium~chloride}{water}\qquad 2:3\qquad \cfrac{2}{3}\implies \cfrac{2\cdot \frac{580}{2+3}}{3\cdot \frac{580}{2+3}}\implies \cfrac{2\cdot 116}{3\cdot 116}\implies \cfrac{232}{348}$

3 0

4 years ago

Use the the factor theorem to determine wether the first polynomial is a factor of the second. X-3; 2x^2-4x+30

Firdavs [7]

Given the polynomial function

$P(x)=2 x^{2} -4x+30$

If (x-3) is a factor of P(x), then

$P(x)=2 x^{2} -4x+30=(x-3)*Q(x)$ , for some polynomial Q of 1st degree,

Then according to the factor theorem P(3)=0, because P(3)=(3-3)Q(x)=0*Q(3)=0.

Check

$P(3)=2 (3)^{2} -4(3)+30=18-12+30=36$ ≠0

we see that P(3) is not 0, so (x-3) is not a factor of P(x).

Answer: no

6 0

3 years ago

Oblicz -12+4*(-11) -(-5)<br> ------------- <br> 4

Nina [5.8K]

Odpowiedź:

-51

Wyjaśnienie krok po kroku:

Oblicz -12 + 4 * (- 11) - (- 5)

Biorąc pod uwagę wyrażenie

-12 + 4 * (- 11) - (- 5)

Korzystanie z PEDMAS

nawias pierwszy

-12 + 4 * (- 11) +5

Ich mnożenie

-12-44 + 5

Podsumowując

-56 + 5

= -51

8 0

3 years ago