Answer:
speed=d/t
let him cover x distance while walking
running d=4.5-x
s1=x/0.5 km/hr....(1)
s2=4.5-x//5/12.....(2)
atq.....s2=2+s1
s1=2x
s2=54-12x/5
by eqn 1 and 2
s1+s2=2x+54-12x/5
putting value of s2
s1+2+s1=2x+54-12x/5....taking LCM =5
10s1+10= 10x+54-12x
as s1=2x
10s1+10= -2x+54
10s1+10=-s1+54
11s1=44
speed when walking=4km/hr
Answer: {y,x} = {4,2} ) ) ) )4
Step-by-step explanation: y
[2] y = -2x + 8
// Plug this in for variable y in equation [1]
[1] (-2x+8) - x = 2
[1] - 3x = -6
// Solve equation [1] for the variable x
[1] 3x = 6
[1] x = 2
// By now we know this much :
y = -2x+8
x = 2
// Use the x value to solve for y
y = -2(2)+8 = 4
Solution :
{y,x} = {4,2}
Answer:
hey, i might help in english?
Step-by-step explanation:
9514 1404 393
Answer:
610 m²
Step-by-step explanation:
If we extend the horizontal line across the right-hand portion of the figure, then the figure is divided into two rectangles:
bottom: 5 m × 50 m = 250 m²
top: 18 m × 20 m = 360 m²
The sum of these areas is the shaded area:
shaded area = 250 m² +360 m² = 610 m²
