All categories

3 years ago

Solve.

1 answer:

4 0

The answer would be D. (3, -4).

Work:
3 = x
-4 = y
3 • 5 = 15
-4 • 2 = -8
15 + -8 = 7

To check: y = x - 7
-4 = 3 - 7
3 - 7 = -4

You might be interested in

If berry has 30 ounces of coke and sells each ounce for 8 bucks an ounce how many ounces do you get if you spend 13 dollars on c

pentagon [3]

Answer would be $104

8 0

3 years ago

What is the first quartile, Q1, of the data set?

Kryger [21]

It is 28 because you have to take the median out then go to the first set of data and find the median of that.

4 0

4 years ago

A car travels 14km in 25mins . Find out how far the car can travel in 5 hours if the speed remains the same ?

jekas [21]

<h3><u>Answer :- </u></h3>

168 km ...

<h3><u>Explanation :- </u></h3>

It is given that the car travels 14km in 25 minutes..

Now , assume that the distance the car travel in 5 hours be x..

Since 1 hour = 60 minutes..
5 hours = 300 minutes ..

• Thus , The two given statements are :-

14km -----------------> 25 minutes..
And, x km -------------> 300 minutes..

The distance travelled by car and the time taken by the car is directly proportional to each other....

$\frac{14}{25} = \frac{x}{300}$

$= x = 168km$

• Hence , Car can travel 168km in 5 hours ..

Hope this helps you :)

6 0

2 years ago

15 players for a softball team show up for a game: (a) How many ways are there to choose 10 players to take the field? 3003 (b)

prohojiy [21]

Answer:

(a) 3003 ways

(b) 10897286400 ways

Step-by-step explanation:

Given

$n = 15$ --- 15 players

Solving (a) Ways of selecting 10 players.

This implies combination.

So, we have:

$r=10$

Using:

$^nC_r = \frac{n!}{(n-r)!r!}$

We have:

$^{15}C_{10} = \frac{15!}{(15-10)!10!}$

$^{15}C_{10} = \frac{15!}{5!10!}$

Simplify

$^{15}C_{10} = \frac{15*14*13*12*11*10!}{5!10!}$

$^{15}C_{10} = \frac{15*14*13*12*11}{5!}$

$^{15}C_{10} = \frac{15*14*13*12*11}{5*4*3*2*1}$

$^{15}C_{10} = \frac{360360}{120}$

$^{15}C_{10} = 3003$

Solving (b) Ways of assigning positions to 10 players.

This implies permutation.

So, we have:

$r=10$

Using:

$^nP_r = \frac{n!}{(n-r)!}$

We have:

$^{15}P_{10} = \frac{15!}{(15-10)!}$

$^{15}P_{10} = \frac{15!}{5!}$

Solve each factorial

$^{15}P_{10} = \frac{1307674368000}{120}$

$^{15}P_{10} = 10897286400$

Solving (c) Ways of choosing at least 1 woman

We have:

$Men = 10$

$Women = 5$

Ways of selecting 10 players is: (a) 3003 ways

Since the number of men are 10, there is 1 way of selecting 10 men (i.e. selection without women)

Using complement rule:

At least 1 woman = Total - No woman

$At\ least\ 1\ woman = 3003 - 1$

$At\ least\ 1\ woman = 3002$

5 0

3 years ago

Please help, I would appreciate it

max2010maxim [7]

Answer:

-5x + 8y = -21

3x - 4y = 15

8y = 5x - 21

y = 5/8x - 21/8

3x - 4y = 15

-4y = -3x + 15

y = 3/4x - 15/4

5/8x - 21/8 = 3/4x - 15/4

-1/8x = -9/8x

x = 9

3x - 4y = 15

3(9) - 4y = 15

27 - 4y = 15

-4y = -12

y = 3

(9, 3)

3 0

3 years ago

Read 2 more answers