Answer:
Step-by-step explanation:
To solve this problem we are going to set Python as the language.
books = ["a", "b", "c", ... , "z"]
selection = list(3) #here we set a list of dimension 3 as 3 are supposed to be selected
for book in books: #here we parse into the books list
If book in selection: continue #in order to obtain different books, if the book #already in selection list, then we jump
selection.append(random.choice(books)) #if not, we add the book to #selection
print(selection)
Answer:
119.4
Step-by-step explanation:
Answer:
Step-by-step explanation:
One approach would be to begin the indicated multiplication: Multiply a² by a, obtaining a³, which is the first term of the product a3 – a2b + ab2 + a2b – ab2 + b3. Please use " ^ " to indicate exponentiation, or (²) or (³):
a(a² - ab + b²) = a³ (plus 2 more terms, which are -a²b and ab²).
Here we are applying the distributive property of multiplication.
Answer:
5
Step-by-step explanation:
from the attached diagram, we can see that
LN = MP
3x + 1 = 8x -4
8x-3x = 1 + 4
5x = 5
x = 1
hence
LN = 3x+ 1 = 3(1) + 1 = 4
NM = 4x-1 = 4(1) - 1= 3
hence by Pythagorean formula,
diagonal NP = diagonal LM = √( 3² + 4²) = √25 = 5
Check the picture below, notice the red asymptotic lines.
now, recall that