Ask question

Ask question

All categories

3 years ago

9

Plsss help me! I’m stuck :(

1 answer:

bixtya [17]3 years ago

5 0

Answer:15 = 2 16 = -1.25

Step-by-step explanation:If you need any more help I'm usually available between 9 a.m - 3:50 pm

You might be interested in

Janet saved $400 dollars. She decided to spend 130 on clothes. What percentage of her money did she spend on clothes?

adell [148]

Answer:

32.5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

How can you tell if a system of equations has infinite solutions?

kirill [66]

To tell if an equation has infinite solutions, the equation will be equal to each other.

For example,

x = x
x + 1 = x + 1
x - y = x - y

And so on...

And in special cases,

0x = 0
0x = 0(y + 1)

They have infinite solutions because there's no constant to determine the variable.

4 0

3 years ago

1<br> Find the slope of the following graph and write your result in the empty box.<br> Answer:

Viktor [21]

Answer:

y = 2x

Step-by-step explanation:

Slope = $\frac{y}{x} =\frac{2}{1}$

4 0

3 years ago

James is making a paper chain from different colored paper strips. He joins the links in the following pattern: red, blue, red,

Whitepunk [10]

Answer:

red

Step-by-step explanation:

1-red

2-blue

3-red

4-blue

5-red

6-blue

7-red

8-blue

9-red

10-blue

11-red

12-blue

13-red

14-blue

15-red

16-blue

17-red

18-blue

19-red

20-blue

21-red

22-blue

23-red

im so smart fr

8 0

2 years ago

Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.

Bas_tet [7]

Answer:

The function touches the damping factor

at x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

The x-intercept of f(x) is

at x= $n\pi$

Step-by-step explanation:

Given function is f(x)= $e^{-3x} sin(x)$ and damping factor as y= $e^{-3x}$ and y= $(-1)e^{-3x}$

To find when function touches the damping factor:

For f(x)= $e^{-3x} sin(x)$ and y= $e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=e^{-3x}$

$sin(x)=1$

x= $\frac{(4n-3)\pi}{2}$

For f(x)= $e^{-3x} sin(x)$ and y= $(-1)e^{-3x}$

Equating the both the equation,

$e^{-3x} sin(x)=(-1)e^{-3x}$

$sin(x)=(-1)$

x= $\frac{(4n-1)\pi}{2}$

Therefore, The function touches the damping factor x= $\frac{(4n-3)\pi}{2}$ and x= $\frac{(4n-1)\pi}{2}$

To find x-intercept of f(x):

For x-intercept, y=0

f(x)= $e^{-3x} sin(x)$

y= $e^{-3x} sin(x)$

$e^{-3x} sin(x)=0$

Hence, $e^{-3x}$ is always greater than zero.

Therefore, $sin(x)=0$

x= $n\pi$

Thus,

The x-intercept of f(x) is at x= $n\pi$

7 0

4 years ago