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wlad13 [49]
3 years ago
14

I need help with answering question 16 on spring board algebra 2 pg. 35 the questions says solve the system using substitution t

he equation is : {4y + 19 = x and below that is 3y-x=4 I just need to be shown how to do it

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0

Answer:

x = 147

y = 32

Step-by-step explanation:

I got a bit confused by what you said, but I think you need help being shown how to do 16, so hopefully the following will help!

So to use substitution you "plug in" the expression into each other. Here is what to do for 16!

[] First, we need to find which expression can be plugged in. The first one works! It is set equal to x, so we can easily plug it in.

[] Now, we need to set up our equation!

3y - x = -13

      /\

4y + 19 = x

3y - 4y + 19 = -13

[] Now, we <u>solve for y</u> and simplfy!

3y - 4y + 19 = -13

-y = -32

(I subtracted 19 for both sides and combined the y's)

Now I am going to add -y and -32 to both sides so I can have it be positive.

y = 32

[] Last, but not least, we <u>solve for x</u>!

- Plug the y you just solved into the equation for x

4y + 19 = x

4(32) + 19 = x

128 + 19 = x

147 = x

(hopefully this is correct, have a nice day!)

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3 years ago
The table shows some values of a function of the form y
kherson [118]

The value of c, the constant of the function y = ax² + bx + c, exists -3.

<h3>What is an equation?</h3>

An equation exists as an expression that indicates the relationship between two or more numbers and variables.

Given that: y = ax² + bx + c

At point (4, 21)

21 = a(4²) + 4b + c .......(1)

At point (5, 32)

32 = a(5²) + 5b + c .........(2)

At points (6, 45)

45 = a(6²) + 6b + c .......(3)

Therefore, the value of a = 1, b = 2 and c = -3.

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4 0
1 year ago
Reese's truck can go 1,040miles on a full tank of 52gallons of gas. Find the rate of miles per gallon.
Vesna [10]

Answer:

20

Step-by-step explanation:

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8 0
3 years ago
Which are the roots of x^2-4x+4=20
Marysya12 [62]
X2+-4x+4=20 the final answer is 20!
3 0
4 years ago
Mr. Brown has taken out a loan of value $1,000 with a 5% APR. He has been paying off the loan at a constant rate of r = $150/yea
Dafna11 [192]

Answer:

\frac{dp}{dt} = 0.05P - 150

Step-by-step explanation:

Let P(t) be the balance of the loan at time t years,

Let P(t) will satisfy \frac{dp}{dt}=rP-R

where r = annual interest rate

          R = per year payment rate

          R = $150/year

          r = \frac{5}{100} = 0.05  \frac{5}{100}

Now we have the following picture,

Interest            Balance          Payment

5%           ⇒          P(t)       ⇒     $150/year

(0.05)

Therefore, a linear ODE satisfied by P(t) is given by

\frac{dp}{dt} = 0.05P - 150

6 0
3 years ago
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