IQR = 6
First locate the median
at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles
and
located at the centre of the data to the left and right of the median.
Note that if any of the above are not whole values then they are the average of the values either side of the centre.
rearrange data in ascending order
15 16 ↓17 17 18 21 22 ↓23 25
↑
= 18
=
= 16.5
=
= 22.5
IQR =
-
= 22.5 - 16.5 = 6
Answer:
92 ft
Step-by-step explanation:
Assume the garden has the shape shown below.
The length of fencing equals the distance around three sides of the rectangle plus that around the semicircle.
1. Around the rectangle
Distance = 28 ft + 14 ft + 28 ft = 70 ft
2. Around the semicircle
For a circle.
C = 2πr
For the semicircle,
½C =½(2πr) = πr
D = 14 ft, so
r = 7 ft

3. Total distance
Distance = 70 ft + 22 ft = 92 ft
Jordan will need 92 ft of fencing.
the equation is 2x-1 right so all you have to do is plug and go
2x-1
2x10-1
20-1
19
so your answer would be A)19
Given:
A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .
To find:
The fourth-degree polynomial function in factored form.
Solution:
The factor for of nth degree polynomial is:

Where,
are n zeros of the polynomial.
It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:


![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
On further simplification, we get

![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)
Therefore, the required fourth degree polynomial is
.
Answer:
The volume of the cereal box is 276.25 inches