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soldi70 [24.7K]
3 years ago
13

531 times what equals 5,310

Mathematics
2 answers:
Leya [2.2K]3 years ago
4 0

Answer:

10

531 x 10 = 5,310

Nikitich [7]3 years ago
4 0

Answer:

10

Step-by-step explanation:

To figure this out, u can always reverse multiplication by division.

For example:

5,310/531= 10

So, 531 x 10 would be 5,310

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A rectangular board is 1.5 meters long and 0.8 meters wide. What is the area of the board in square millimeters? Do not round yo
serious [3.7K]
Convert 1.5 and 0.8 from meters to millimeters,

1500*800,

A=120,000
8 0
3 years ago
Read 2 more answers
Holly spends 7 3/5 hours in school each day. Her lunch is 1/2 hour long, and she spends 7/10 of a hour switching classes. The re
Ira Lisetskai [31]
<span>
y = 7 + 3/5
y = 35/5 + 3/5
y = 38/5
y = 2*(38/5)
y = 76/10
---
lunch time:
z = 1/2
z = 5*(1/2)
z = 5/10
---
time switching classes:
w = 7/10
---
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (76/10 - 5/10 - 7/10)/6
x = (76 - 5 - 7)/(10*6)
x = (64)/(10*6)
x = (2*2*2*2*2*2)/(2*5*2*3)
x = (2*2*2*2)/(5*3)
x = 16/15

x = 1.0666666666
---
check:
y = 7 + 3/5
y = 7.6
z = 1/2
z = 0.5
w = 7/10
w = 0.7
y - 6x - z - w = 0
6x = y - z - w
x = (y - z - w)/6
x = (7.6 - 0.5 - 0.7)/6
x = 1.0666666666

answer:
 1.07 hours</span>
5 0
3 years ago
Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu
Alona [7]

Answer:

We have the equation

c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

4 0
3 years ago
PLEASE HELP ME PLEASE!!
erastova [34]

Answer:

Is that you in your pfp?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is 11/15= 8/15-w
victus00 [196]

Answer: w= 1/5

Step-by-step explanation:

11/15=8/15 -w

-W= 8/15 -11/15

-w= 8-11/15 =-3/15

-w=-3/15

w=3/15= 1/5

4 0
3 years ago
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