Question

You roll a number cube twice. What is the probability of rolling a 2 first and then rolling an odd number?

Answer 1

You have a 50% to 75% chance 

Answer 2

Answer:

The probability is $\frac{1}{12}$

Step-by-step explanation:

Define the events $A$ and $B$ as the events "rolling a 2" and "rolling an odd number", respectively. Notice that the result of every rolling is independent of the previous results, so the event $A\cap B$ describes the phenomenon we are analazying.

On the other hand, we have that the probability of rolling a 2 is $\frac{1}{6}$ and the probability of rolling an odd number is $\frac{1}{2}$, thus

$P(A\cap B) = P(A)\cdot P(B) = \frac{1}{6}\cdot \frac{1}{2} = \frac{1}{12}$.