sinA+sinB+sinC
=2sin(A+B)/2cos(A-B)/2+sin C
=2sin(pi-C)/2cos(A-B)/2+2sin C/2cosC/2
=2cosC/2(cos(A-B)/2+cos(A+B)/2)
=4 cos A/2 cos B/2 cos C/2
= RHS
Answer:f(x) = 2x³ - x² - 9x + 6
0 = 2x³ - x² - 9x + 6
0 = 2x³ + 3x² - 4x² - 3x - 6x + 6
0 = 2x³ + 3x² - 3x - 4x² - 6x + 6
0 = x(2x²) + x(3x) - x(3) - 2(2x²) - 2(3x) + 2(3)
0 = x(2x² + 3x - 3) - 2(2x² + 3x - 3)
0 = (x - 2)(2x² + 3x - 3)
0 = x - 2 or 0 = 2x² + 3x - 3
+ 2 + 2 x = -3 ± √(3)² - 4(2)(-3)
2 = x 2(2)
x = -3 ± √9 - 4(-6)
4
x = -3 ± √9 + 24
4
x = -3 ± √33
4
x ≈ -3 ± 5.74
4
x ≈ -3 + 5.74 or x ≈ -3 - 5.74
4 4
x ≈ 2.74 or x ≈ -8.74
4 4
x ≈ 0.685 or x ≈ -2.185
Step-by-step explanation:
Answer:
y = 2x + 1
Step-by-step explanation:
Given a point and the slope, we can plug in these values into the equation to find the value of b:
y = mx + b
3 = 2(1) + b
3 = 2 + b
1 = b
Plug b into the equation:
y = 2x + 1
The function is
Graph attached
There is one real zero only
That's-1.047
