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Gekata [30.6K]
3 years ago
8

Identify an appropriate method to solve the equation x²- 14 x+ 48= -10

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

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Is the awnser for this problem
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Mr. Charles cut fresh roses from his garden and gave 10 roses to his neighborhood. then gave half of what was left to his niece.
Vlad [161]
14+14=28
28+10=38 roses
8 0
3 years ago
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What is the answer ​
Gnom [1K]

Answer:

lol ty for the points

Step-by-step explanation:

4 0
3 years ago
Let alpha and beta be conjugate complex numbers such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}
miskamm [114]

Answer:

-3+i\sqrt{3} , 1+\sqrt{3}

Step-by-step explanation:

Given that alpha and beta be conjugate complex numbers

such that frac{\alpha}{\beta^2} is a real number and alpha - \beta| = 2 \sqrt{3}.

Let

\alpha = x+iy\\\beta = x-iy

since they are conjugates

\alpha-\beta = x+iy-(x-iy)\\= 2iy= 2i\sqrt{3} \\y =\sqrt{3}

\frac{\alpha}{\beta^2} }\\=\frac{x+i\sqrt{3} }{(x-i\sqrt{3})^2} \\=\frac{x+i\sqrt{3}}{x^2-3-2i\sqrt{3}} \\=\frac{x+i\sqrt{3}((x^2-3+2i\sqrt{3}) }{(x^2-3-2i\sqrt{3)}(x^2-3-2i\sqrt{3})}

Imaginary part of the above =0

i.e. \sqrt{3} (x^2-3)+2x\sqrt{3} =0\\x^2+2x-3=0\\(x+3)(x-1) =0\\x=-3,1

So the value of alpha = -3+i\sqrt{3} , 1+\sqrt{3}

3 0
3 years ago
Find the 8th term of 27,36,48
Sonbull [250]

Step-by-step explanation:

the sequence is a geometric sequence

simply use the formula:

t(n) = a * (r)^n-1

where n = 8, a = 27, r = 4/3

4 0
3 years ago
The coordinate m is 2.5 and mn=4. What are the possible coordinates for n
steposvetlana [31]
Refer to the figure shown below.

The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.

Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²

This represents a circle with center at (2,5) and radus = 4.

Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.

7 0
3 years ago
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