Identify an appropriate method to solve the equation x²- 14 x+ 48= -10

The table shows the amount of money that Bradford saved in his savings account after different amounts of time.

DochEvi [55]

Nice of you to offer 50 points

the constant of proportinality is the sloep or
$\frac{change(y)}{change(x)}$
x is independent variable and y is dependent variable

the independent variable influences the value of the dependent variable

in this case, the number of months influences the amount of money saved

to find the slope, you do
x=number of months
y=amount

we have
4months, $50
8 months, $100
18 months, $225

or
(x,y)
(4,50)
(8,100)
(18,225)

we can compare

the slope between the points (a,b) and (c,d) is
(d-b)/(c-a)
we can take the slope between any 2 points (assuming the slope is the same, which it is)

(4,50) and (8,100)
slope=(100-50)/(8-4)=50/4=25/2=12.5

the slope is 12.5

2nd option is the answer

3 0

3 years ago

Read 2 more answers

Please help me this is one step equations.

Tju [1.3M]

Answer:

1.81

2.36

3.40

4.54

5.80

6.-40

7.-60

Step-by-step explanation:

1.y= 9*9

2.a = 3*12

3.n = -4 * -10

4. x = 9*6

5.d = -8 * -10

6. t = -2 * 20

7. g = 10* -6

5 0

3 years ago

I need help in these questions

Salsk061 [2.6K]

Answer:

see explanation

Step-by-step explanation:

All of these questions use the external angle theorem, that is

The external angle of a triangle is equal to the sum of the 2 opposite interior angles.

18

∠3 = 43° + 22° = 65°

19

∠2 + 71 = 92 ( subtract 71 from both sides )

∠2 = 21°

20

90 + ∠4 = 123 ( subtract 90 from both sides )

∠4 = 33°

21

2x - 15 + x - 5 = 148

3x - 20 = 148 ( add 20 to both sides )

3x = 168 ( divide both sides by 3 )

x = 56

Hence ∠ABC = x - 5 = 56 - 5 = 51°

22

2x + 27 + 2x - 11 = 100

4x + 16 = 100 ( subtract 16 from both sides )

4x = 84 ( divide both sides by 4 )

x = 21

Hence ∠JKL = 2x - 11 = (2 × 21) - 11 = 42 - 11 = 31°

3 0

4 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

case A) $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

case B) $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

case C) $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

case D) $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

What are all the angle measures for right triangle ABC?

Alenkasestr [34]

Answer:

$\alpha = 60°,\:\beta = 30°, \: 90°$

Step-by-step explanation:

$Arccos( \frac{ \sqrt{3} }{2} ) = \beta \\ Arccos( \cos \: 30 \degree ) = \beta \\30 \degree = \beta \\ \therefore \: \alpha = 60 \degree \\ remaining \: angle = 90 \degree \\$

3 0

3 years ago