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Aleks04 [339]
3 years ago
6

Use the drawing tool(s) to form the correct answer on the provided graph.

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer: Mark points and draw a lines threw them (-1, -10) and (3, 10)

Step-by-step explanation:

Drawing the inverse of a line means taking two points and reversing them, two points on the graph and reversing them would be like this,

(-10, -1) and making it (-1, -10)

and a different point

(10, 3) and making it (3, 10)

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The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
Choose the equation of the horizontal line that passes through the point (−2, −1). (4 points)
Anni [7]

Answer:

y=-1 : )

Step-by-step explanation:

(Brainliest Please)

8 0
2 years ago
A car is traveling at 47 mph. If its tires have a diameter of 27 inches, how fast are the car's tires turning? Express the answe
Amiraneli [1.4K]

Answer:

3676.44 rad/min

Step-by-step explanation:

It is a problem about the angular speed of the car's wheel.

You can calculate the angular speed by using the following formula, which relates the tangential speed of the wheels (the same as the speed of the car) with the angular speed:

\omega=\frac{v}{r}    ( 1 )

v: speed of the car = tangential speed of the wheels = 47mph

r: radius of the wheels = 27/2 in = 13.5 in

you change the units of the speed:

47mph*\frac{63360in}{1mille}*\frac{1h}{60min}=49632\frac{in}{min}

next, you replace the values of v and r in the equation (1):

\omega=\frac{v}{r}=\frac{49632in/min}{13.5in}=3676.44\frac{rad}{min}

Then, the car's tires are turning with an angular speed of 3676.44 rad/min

8 0
3 years ago
If r = 10 units and x = 14 units, then what is the volume of the cylinder shown above?
Agata [3.3K]

Answer:

4398.23 is the volume

5 0
3 years ago
Read 2 more answers
To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?
Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0
3 years ago
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