Question

If we dcrease the radius of each cylinder by 2m , which one has the greater volume give your answer rounded to the nearest tenth use 3.14 for pi

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Given

The question is incomplete, as the cylinders are not given.

Required

The cylinder with greater volume

To answer this question, I will assume the following dimensions.

Cylinder 1

$r = 5$

$h = 10$

Cylinder 2

$r = 7$

$h = 5$

Volume is calculated as:

$V = \pi r^2h$

When the radius is reduced by 2, the formula becomes

$V = \pi (r - 2)^2h$

For the first cylinder, we have:

$V_1 = \pi (r - 2)^2h$

$V_1 = 3.14 * (5 - 2)^2 * 10$

$V_1 = 3.14 * 3^2 * 10$

$V_1 = 3.14 * 9 * 10$

$V_1 = 282.6$

For the second cylinder, we have:

$V_2 = \pi (r - 2)^2h$

$V_2 = 3.14 * (7 - 2)^2 * 5$

$V_2 = 3.14 * 5^2 * 5$

$V_2 = 3.14 * 25 * 5$

$V_2 = 392.5$

Cylinder 2 has a greater volume because 392.5 > 282.6

Note: Irrespective of the dimension of the cylinders, the above step works fine.