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Igoryamba
3 years ago
6

Which keys can be pressed to change the cuboid/frame selector color on remotasks lidar course

Computers and Technology
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

c h b l

color palette and a lightbulb

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Any test practices end-user he or she does by step by step process for quality testing. Some end-user will have a checklist to do while testing any software or hardware installing.

A hacking end-user has to do the test process if he or she has to follow some steps during testing.

<u>Explanation:</u>

This process is called penetration testing, in other words, it is called pen-testing.

1. In the digital world, security plays an important role. Before any potential incidents taking place, security threats have to handle properly. Before hacking takes place for pc or workstation or desktop, the end-user has to identify and take proper action.

Mostly all threats happen in c:\users\appdata folder in windows operating system

2. Penetration testing is used to for hacking purpose testing.

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b. Best practice testing on network security, computer system, web system and find vulnerability check.

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Which item can be added to Outlook messages, like a Word document or PowerPoint presentation, that takes standard bulleted lists
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WordArt

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2 years ago
If you want to wrap text so that it fits a particular cell size, which formatting section would you use?
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Write a Java program to encrypt and decrypt a phrase using two similar approaches, each insecure by modern standards. The first
xeze [42]

Answer:

See explaination

Explanation:

//CryptoManager.java

public class CryptoManager {

static int LOWER_BOUND=32;

static int UPPER_BOUND=95;

/*This method determines if a string is within the allowable bounds of ASCII

codes according to the LOWER_BOUND and UPPER_BOUND characters. The parameter

plainText is the string to be encrypted. The method returns true if all

characters are within the allowable bounds, false if any character is outside.*/

public static boolean stringInBounds (String plainText)

{

boolean flag=true;

//determines if a string is within the allowable bounds of ASCII

//codes according to the LOWER_BOUND and UPPER_BOUND characters.

for(int i=0;i<plainText.length();i++)

{

if(!((int)plainText.charAt(i)>=LOWER_BOUND && (int)plainText.charAt(i)<=UPPER_BOUND))

{ //false if any character is outside the bounds

flag=false;

break;

}

}

//returns true if all characters are within the allowable bounds

return flag;

}

/*This method encrypts a string according to the Caesar Cipher. The integer key

specifies an offset and each character in plainText is replaced by the character

the specified distance away from it. The parameter plainText is an uppercase

string to be encrypted. The parameter key is an integer that specifies the

offset of each character. The method returns the encrypted string.*/

public static String encryptCaesar(String plainText, int key)

{

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//encrypted text

String res="";

//encryption

for(int i=0;i<plainText.length();i++)

{

res+=Character.toString((char) ((int)plainText.charAt(i)+key));

}

//return result

return res;

}

/* This method decrypts a string according to the Caesar Cipher. The integer

key specifies an offset and each character in encryptedText is replaced by

the character "offset" characters before it. This is the inverse of the

encryptCaesar method. The parameter encryptedText is the encrypted string

to be decrypted, and key is the integer used to encrypt the original text.

The method returns the original plain text string.*/

public static String decryptCaesar(String encryptedText, int key){

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//decrypted text

String org="";

//encryption

for(int i=0;i<encryptedText.length();i++)

{

org+=Character.toString((char) ((int)encryptedText.charAt(i)-key));

}

//return result

return org;

}

public static int Wrap_around(int key)

{

while(key>UPPER_BOUND)

{

key-=(UPPER_BOUND-LOWER_BOUND);

}

return key;

}

/* This method encrypts a string according to the Bellaso Cipher. Each character

in plainText is offset according to the ASCII value of the corresponding

character in bellasoStr, which is repeated to correspond to the length of

plaintext. The method returns the encrypted string.*/

public static String encryptBellaso(String plainText, String bellasoStr)

{

//encrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<plainText.length())

{

bellasoStr+=bellasoStr.substring(0,(plainText.length()-bellasoStr.length()));

}

//encryption

for(int i=0;i<plainText.length();i++)

{

char c=(char)Wrap_around((int)plainText.charAt(i)+(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

/*

This method decrypts a string according to the Bellaso Cipher. Each character

in encryptedText is replaced by the character corresponding to the character in

bellasoStr, which is repeated to correspond to the length of plainText. This is

the inverse of the encryptBellaso method. The parameter encryptedText is the

encrypted string to be decrypted, and bellasoStr is the string used to encrypt

the original text. The method returns the original plain text string.*/

public static String decryptBellaso(String encryptedText, String bellasoStr)

{

//decrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<encryptedText.length())

{

bellasoStr+=bellasoStr.substring(0,(encryptedText.length()-bellasoStr.length()));

}

//decryption

for(int i=0;i<encryptedText.length();i++)

{

char c=(char)Wrap_around((int)encryptedText.charAt(i)-(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

}

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3 years ago
How do you fix this windows 7 screen​
tensa zangetsu [6.8K]

Try restarting it. If you can’t restart because the screen is frozen maybe just turn it off and back on. If you already tried restarting and it still didn’t fix the problem, just give it some time. The computer will reset itself eventually which should fix the problem.

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