WILL GIVE BRAINLEST 100Pts!
2 answers:
Answer:
25.
See the graph attached.
All required points are labeled.
26.
x- intercept is the point when the value of the car drops to zero, after 12 and 15 years respectively.
y- intercept is the point after initial depreciation immediately after sale.
Intersection of the graphs is the point at which the value of each car is same, $18000 after 3 years from sale.
Answer:
Step-by-step explanation:
f(A) = 30000 (1 - 0.2) - 2000(t)
f(A) = 30000(0.8) - 2000(t)
f(A) = 24000 - 2000(t)
0 = 24000 - 2000(t)
t = 12
f(B) = 25000(1 - 0.1) - 1500(t)
f(B) = 25000(0.9) - 1500(t)
f(B) = 22500 - 1500(t)
0 = 22500 - 1500(t)
t = 15
22500 - 1500(t) = 24000 - 2000(t)
500t = 1500
t = 3
22500 - 1500(3) = 18000
26) The y intercepts are the value of the new car when purchased.
The x intercepts are when the car value drops to zero due to depreciation.
The intersection occurs when their depreciated values are equal.
(The intersection does not occur properly on the graph because of camera image distortions)
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Answer:
second option
Step-by-step explanation:
Given
f(x) = (x - 7)(x + 4)(3x - 2)
To find the zeros let f(x) = 0, that is
(x - 7)(x + 4)(3x - 2) = 0
Equate each factor to zero and solve for x
x - 7 = 0 ⇒ x = 7
x + 4 = 0 ⇒ x = - 4
3x - 2 = 0 ⇒ 3x = 2 ⇒ x =
zeros are x = - 4, x = , x = 7