3 years ago

Hey guy pls help explain answer no links

Mathematics

1 answer:

laiz [17]3 years ago

8 0

Answer:

4, 5

Step-by-step explanation:

the mode is 4 since mode is the number/s that appear most. Median is the number in the middle when the range is in order. That is 5

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Let f(x) = 8x3 − 28x + 61 and g(x) = 2x + 5. Find f of x over g of x.

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Answer:

$4x^2-10x+11+\frac{6}{2x+5}$

Step-by-step explanation:

The given functions are:

$f(x)=8x^3-28x+61$ and $g(x)=2x+5$

By algebraic properties of functions;

$\frac{f(x)}{g(x)}=\frac{8x^3-28x+61}{2x+5}$

We perform the long division of the two polynomials as shown in the attachment.

Therefore:

$\frac{8x^3-28x+61}{2x+5}=4x^2-10x+11+\frac{6}{2x+5}$

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