All categories

2 years ago

What is the distance of a car traveling with a velocity of 20 m/s north in 5 seconds

Mathematics

1 answer:

blsea [12.9K]2 years ago

3 0

distance=velocity×

(time)

20(5)

=100m/S

You might be interested in

Which of the binomials below is a factor of this trinomial? x2 + 8x + 16

Gre4nikov [31]

X^2 + 8x + 16 =
(x + 4)(x + 4) or (x + 4)^2

4 0

3 years ago

What's the following sequence

Dmitry [639]

Your answer is A !! go for it !!

8 0

2 years ago

Read 2 more answers

SinA=(7/25), determine CosA and TanA exactly

bixtya [17]

Answer:

Cos A = 24/25 & Tan A = 7/24

Step-by-step explanation:

See the attached figure.

Construct a right triangle and sign one angle as A

So, Sin A = opposite/hypotenuse = 7/25

∴hypotenuse = 25 and opposite = 7

∴ adjacent = √(25² - 7² ) = √576 = 24

∴ Cos A = adjacent/hypotenuse = 24/25

And

Tan A = opposite/adjacent = 7/24

5 0

2 years ago

Find the value of x in the diagram shown below.

koban [17]

Answer:

a) ∡ADC = 270°

b) ∠DAE = 38°

Step-by-step explanation:

Using Inscribed Angle Theorem :

∡ADC = 2 x ∠ABC
∡ADC = 2 x 135°
∡ADC = 270°

Similarly :

∠DAE = 1/2 x ∡DE
∠DAE = 1/2 x 76°
∠DAE = 38°

5 0

2 years ago

Read 2 more answers

Select the correct answer.

Butoxors [25]

Answer:

Approximately 163 seconds (A)

Step-by-step explanation:

Line up 192 months on the x-axis with the line of best fit then run it across to the y-axis and it should be around 163 seconds.

8 0

3 years ago