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Komok [63]
3 years ago
12

Como se escribe 696,543,098 en letra lo ocupo para una tarea

Mathematics
1 answer:
Sav [38]3 years ago
8 0

Answer:

seiscientos noventa y seis millones quinientos cuarenta y tres mil noventa y ocho

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A person who is 2 m tall casts a shadow that is 5 m long. At the same time, a building casts a shadow that is
VMariaS [17]

Answer:

9.6

Step-by-step explanation:

First you figure out that the shadow is 2.5 times larger than what is casting it. Then you divide 24 by 2.5.

4 0
2 years ago
The square ABCD has side length 20 cm,
bogdanovich [222]

Answer:

AE=22.4

Step-by-step explanation:

BE is 1/2 of BC

BC is 20 cm                 All sides of a square are equal

BE = 1/2 BC                  Property of a midpoint.

BE = 10

Now just use Pythagorus

AB^2 + BE^2 = AE^2

AE^2 = 20^2 + 10^2   Perform the sqrs

AE^2 = 400 + 100      Add the terms

AE^2 = 500                Take the square root of both sides

√AE^2 = √500

AE = 22.36

AE ≈ 22.4

6 0
3 years ago
I will give brainliest to whoever posts how to make a pizza or answer what 50 + 50 is
Gre4nikov [31]

Answer:

100 :P when u read to fast n then put 2500 lol

Step-by-step explanation:

4 0
3 years ago
Which ordered pairs in the form (x, y) are solutions to the equation
Levart [38]
The answer is a and c
4 0
2 years ago
The sums that appear when two fair? four-sided dice? (tetrahedrons) with sides 1?, 2?, 3?, and 4 are tossed
Karolina [17]

Answer:

The possible sums are 2, 3, 4, 5, 6, 7 & 8 (but they're not all equally likely)

Step-by-step explanation:

For example, the only way to get a sum of 2 is to roll a 1 and then a 1

And the only way to get a sum of 8 is to roll a 4 and then a 4 (imagine you don't roll the two dice simultaneously; this will help you to see the "other possibilities" that aren't obvious at first)

The probability of rolling a sum of 2 = probability of rolling sum of 8 (1/16 probability for each)

If you roll a 1 then a 2, or a 2 then a 1, there are 2 ways to get a sum of 3

If you roll a 3 then a 1, a 2 then a 2, or a 1 then a 3, there are 3 ways to get a sum of 4

If you roll a 4 then a 1, a 3 then a 2, a 2 then a 3, or a 1 then a 4, there are 4 ways to get a sum of 5 (5 is the most likely sum)

If you roll a 4 then a 2, a 3 then a 3, or a 2 then a 4, there are 3 ways to get a sum of 6

If you roll a 4 then a 3, or a 3 then a 4, there are 2 ways to get a sum of 7

5 0
3 years ago
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