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3 years ago

12

Como se escribe 696,543,098 en letra lo ocupo para una tarea

1 answer:

Sav [38]3 years ago

8 0

Answer:

seiscientos noventa y seis millones quinientos cuarenta y tres mil noventa y ocho

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I need help un #24 plz

lesantik [10]

The picture is blurry

8 0

3 years ago

Subtract these fractions:<br> 2/3 - 5/8

monitta

Answer:

1/24 ; 0.04166667

Step-by-step explanation:

2 5

/ - / = 5*3 / 8*3 = 16/24 - 15/24 = 16-15/24 = 1/24

3 8

8 0

4 years ago

Read 2 more answers

In a recent year, 19.4% of all registered doctors were female. If there were 52,500 female registered doctors that year, what wa

sukhopar [10]

Answer: 10,185 registered female doctors.

Step-by-step explanation: We basically want to find how many females were doctors, if 19.4% of the 52,500 females were registered doctors. Basically we want to find 19.4% of 52,500. We will write an equation that works to solve this problem.

19.4/100 = x/52,500 (This equation represents that 19.4% out of 100% is x out of the 52,500 registered doctors.) Solve for x.

19.4/100 x 52,500 = x/52,500 x 52,500.

(19.4 x 52,500 = 1,018,500/100 = 10,185. And, x/52,500 x 52,500 = x.

10,185 = x.

So, 19.4% of all registered doctors would be 10,185 females out of 52,500 females.

3 0

3 years ago

The data set represents a month-to-month progression of gasoline prices over the course of several months in an unspecified city

Tresset [83]

The quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

<h3>What is the general form of a quadratic equation?</h3>

The general form of the quadratic equation is given by;

$\rm ax^2+bx+c=0$

Where; a, b, and c are the constants.

x; 0 1 2 3 4 5

y; 2.82 3. 29 3. 46 3. 33 2. 88 2. 24

From the table when the value of x = 0 the value of y is 2.82.

Then,

$\rm y=ax^2+bx+c\\\\x=0\\\\2.82=a0^2+b(0)+c\\\\c=2.82$

From the table when the value of x = 3 the value of y is 3.33.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.82=a(3)^2+b(3)+c\\\\9a+3b+2.82=2.82\\\\9a=-3b\\\\b=-3a\\\\$

From the table when the value of x = 5 the value of y is 2.24.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.24=a(5)^2+(-3a)(5)+c\\\\25a-15a+2.82=2.24\\\\40a=2.24-2.82\\\\10a=-0.68\\\\a= \dfrac{-0.68}{10}\\\\a=-0.143$

And the value of b is;

$\rm b=3a\\\\b=3(-0.14)\\\\b=0.59$

Therefore,

The quadratic regression equation for this data set is;

$\rm y=ax^2+bx+c\\\\y=-0.143x^2+0.59x+2.82\\\\$

Hence, the quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

To know more about the Quadratic equation click the link given below.

brainly.com/question/14935613

8 0

3 years ago

Which of the following are identities? check all that apply.

Feliz [49]

Answer: (a), (b), (c), and (d)

Step-by-step explanation:

Check the options

$(a)\\\Rightarrow [\sin x+\cos x]^2=\sin ^2x+\cos ^2x+2\sin x\cos x\\\Rightarrow [\sin x+\cos x]^2=1+2\sin x\cos x\\\Rightarrow \Rightarrow [\sin x+\cos x]^2=1+\sin 2x$

$(b)\\\Rightarrow \sin (6x)=\sin 2(3x)\\\Rightarrow \sin 2(3x)=2\sin (3x)\cos (3x)$

$(c)\\\Rightarrow \dfrac{\sin 3x}{\sin x\cos x}=\dfrac{3\sin x-4\sin ^3x}{\sin x\cos x}\\\\\Rightarrow 3\sec x-4\sin ^2x\sec x\\\Rightarrow 3\sec x-4[1-\cos ^2x]\sec x\\\Rightarrow 3\sec x-4\sec x+4\cos x\\\Rightarrow 4\cos x-\sec x$

$(d)\\\Rightarrow \dfrac{\sin 3x-\sin x}{\cos 3x+\cos x}=\dfrac{2\cos [\frac{3x+x}{2}] \sin [\frac{3x-x}{2}]}{2\cos [\frac{3x+x}{2}]\cos [\frac{3x-x}{2}]}\\\\\Rightarrow \dfrac{2\cos 2x\sin x}{2\cos 2x\cos x}=\dfrac{\sin x}{\cos x}\\\\\Rightarrow \tan x$

Thus, all the identities are correct.

4 0

3 years ago