B. (9,126)
<span>y + 18 = 16x
=>y=16x-18
0.5x + 0.25y = 36 (multiply both sides by 4)
=>2x+y = 144
Substitute y=16x-8
=>2x+16x-8=144
=>18x=152
=>x=152/18=9
y=16x-18
=>y=16(9)-18
=>y=144-18=126
Answer: x=9 and y=126</span>
1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
6
Step-by-step explanation:
B(Y)=5x+18
input the values
-2B=5(-6)+18
-2B=-30+18
-2B=-12
B=-12/-2
B=6
Depends on where the underline is
29.95+8.49=38.44. 2x20=40
40.00
- 38.44. ————————-
————
1.56. ======$1.56
