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kondaur [170]
2 years ago
14

Student

Mathematics
1 answer:
Rashid [163]2 years ago
3 0

Answer:

carman and Zackery live the same distance away.

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ludmilkaskok [199]

probably about 1//8th of a day


8 0
3 years ago
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Can someone plz help me if u can’t see zoom in plz help me
kvv77 [185]

Answer:

City 1 and City 2

Step-by-step explanation:

The water is moving down stream, moving from City 1-2-3-4 in that order.

if water was taken a the X mark, the pollutants would have to have come from the cities above where the sample was taken.

Hope this helps!

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2 years ago
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Write an equation: At 2 claps, Joe is in position 7 and walking towards zero at a rate of 3 claps per minute.
frutty [35]

Answer:

I'll assume "position 7" refers to distance and not to the order of other people.  

Step-by-step explanation:

We want an equation of the form y=mx+b, where m is the slope and b is the y-intercept (the value of y when x=0).  We can assume that "claps" is a new measure of distance.  0 claps is the finish.

Let's express the information provided in point format.

"At 2 claps, Joe is in position 7"  is (2,7)  2 is the distance (claps) and 7 is the time (minutes)

And we can say the rate is also the slope of a line.  "rate of 3 claps per minute" is 3c/m, where c is claps and m is minutes.

We can start a line equation by stating y = 3x + b, where we're using the rate, 3 c/m, as the slope, m.

We need to determine the value of b.  We can use the given point (2,7) and solve for m:

y = 3x + b

7 = 3*(2) + b

b = 1

The equation becomes y = 3x + 1

y is the distance in claps and x is the time in minutes.

At a time of 2 claps he is at position of 7.  b = 1 means he started 1 clap further from the finish at 0 claps.

To find the time required to reach the finish, we need to know the total distance, in claps.

6 0
2 years ago
Find the standard form of the complex number 6(cos(30degree) +i sin (30 degree))
Marat540 [252]

Answer:

= 3√3 + 3i

Step-by-step explanation:

Cos 30° = √3/2

Sin 30°  = 1/2

Therefore;

z = 6 (cos 30° + i6 sin 30°)

  = 6 (√3/2) + i 6 (1/2)

   = 3√3 + 3i

6 0
2 years ago
3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third
den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

2x + 3(x + 2) = 2(x + 4) + 55

=  > 2x + 3x + 6 = 2x + 8 + 55

Eliminating 2x from both the sides,

=  > 3x + 6 = 63

=  > 3x = 63 - 6 = 57

=  > x =  \frac{57}{3}  = 19

So, the consecutive odd integers are = 19 , 21 & 23.

3 0
2 years ago
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