Let
x-------> the first number
y-------> the second number
we know that

equation 1

equation 2
substitute the equation 1 in equation 2
![[-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0](https://tex.z-dn.net/?f=%5B-5-y%5D%2Ay%3D-90%20%5C%5C%20-5y-%20y%5E%7B2%7D%20%3D-90%20%5C%5C%20y%5E%7B2%7D%20%2B5y-90%3D0)
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are-12.3117.311
I think it would be b) because you're given a slope of 0, so that leaves you with

, resulting into this

You'd be just left with a continuous horizontal line going through the y-axis of 3 since you're passing the point (2,3), where 3 represents the y-value when your slope is at 0.
Well first off x times x is squaring whatever the number is while x plus x is just multiplying by 2
Answer:
y-7/ 12y+3
Step-by-step explanation:
Answer:
A, -475ft
Step-by-step explanation: