Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Combine like terms.
Subtract 5 from both sides.
Divide both sides by 4.
<h3><u>__________________</u></h3>
Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Knowing that all triangles angles add up to 180*:
24* + x + ? = 180*
Knowing the straight line is 180*:
180* - 122* = 58*
The equation then is:
24* + x + 58* = 180*
Then solve for X:
(82* + x) - 82* = (180*) - 82*
<u>x = 98* or C</u>
