Select all expressions that are equivalent to 10q + 5 ?
1 answer:
Answer:
5q + 5q + 5
2q + 5 + 8q
5(2q + 1)
Step-by-step explanation:
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Answer: A
Step-by-step explanation:
To solve
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)
so
I'm not sure if it is
![f(x)=\sqrt[3]{\frac{x}{7}}-9](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%7D%7B7%7D%7D-9)
or
first one
![f(x)=\sqrt[3]{\frac{x}{7}}-9](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%7D%7B7%7D%7D-9)
replace f(x) with y
![y=\sqrt[3]{\frac{x}{7}}-9](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%7D%7B7%7D%7D-9)
switch x and y
![x=\sqrt[3]{\frac{y}{7}}-9](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7By%7D%7B7%7D%7D-9)
solve for y
![x+9=\sqrt[3]{\frac{y}{7}}](https://tex.z-dn.net/?f=x%2B9%3D%5Csqrt%5B3%5D%7B%5Cfrac%7By%7D%7B7%7D%7D)


replace y with f⁻¹(x)

2nd one
replce f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

if you meant
![f(x)=\sqrt[3]{\frac{x}{7}}-9](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%7D%7B7%7D%7D-9)
then the inverse is

if you meant
![f(x)=\sqrt[3]{\frac{x}{7}-9}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7B%5Cfrac%7Bx%7D%7B7%7D-9%7D)
then the inverse is
Answer:
(3,-7)? I'm not sure.
Answer:
P(1.48<X<15.56) ≈ 0.919 ≈ 91.9%
Step-by-step explanation:
2nd+DISTR --> normalcdf
P(1.48<X<15.56) = normalcdf(1.48,15.56,8,4) ≈ 0.919
Answer:
1/36
Step-by-step explanation:
Getting a 3 is 1/6
Getting a 5 is 1/6
Multiply those and get 1/36