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2 years ago

X^3 • x^4 I need it

Mathematics

2 answers:

Aleks [24]2 years ago

6 0

Answer:

x^7

Step-by-step explanation:

Multiply x3 by x4 by adding the exponents.

Hope it helps! :)

Eddi Din [679]2 years ago

3 0

x^7 Multiply x^3 by x^4 by adding the exponents

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Hey I need some help with this question plz help me

icang [17]

Answer:

Step-by-step explanation:

Let the nickels = x

Let the dimes = y

You don't know the total value of either. Nor do you know the total number of either.

You only know the total value of both together.

7.80 added to anything makes it bigger than 7.80 A is wrong.

y cannot be alone it should be multiplied by 0.5 C is wrong

D is wrong for the same reason A is

B is the correct answer. That is the way you write the problem

Number of Coins and value on one side. Total on the other.

4 0

2 years ago

What is the measure of the missing angle?

Dmitrij [34]

Answer:

for find

97 + 47

144

so --

triangle property

180 - 144

missing angle is 36

4 0

2 years ago

Read 2 more answers

Graph of function F(t) close as possible the value of F(-2)

scoundrel [369]

Answer:

look at the explanation

Step-by-step explanation:

in order to create a f(-2) you would need to know either a table of values or an equation to plug values into . . .saying a function of -2 does not really help, sorry

6 0

3 years ago

Which of the following options results in a graph that shows exponential growth?

poizon [28]

Answer:

$f(x)=0.7(5)^x$

Step-by-step explanation:

$\text{Exponential function: }y=a\cdot b^x$

It is two types of function.

Exponential Growth: If function increase as value of x increase.

In this case, a>0 and b>1

Exponential decay: If function decrease as value of x increase.

In this case, a>0 and 0<b<1

We need to choose exponential growth function.

$\text{Exponential Growth function: }f(x)=0.7(5)^x$

Here a=0.75>0 and b=5>1

Therefore, This function is exponential growth.

7 0

3 years ago

Read 2 more answers

Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye

Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let $\rho(x,y)$ be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

$m=\int\limits \int\limits_D \rho(x,y) \, dA$ .

From the question, the given density function is $\rho (x,y)=xye^{x+y}$ .

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

$I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx$ .

Since D is a rectangular region, we can apply Fubini's Theorem to get:

$I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx$ .

Let the inner integral be: $I_0=\int\limits^1_0xye^{x+y}dy$ , then

$I=\int\limits^1_0(I_0)dx$ .

The inner integral is evaluated using integration by parts.

Let $u=xy$ , the partial derivative of u wrt y is

$\implies du=xdy$

and

$dv=\int\limits e^{x+y} dy$ , integrating wrt y, we obtain

$v=\int\limits e^{x+y}$

Recall the integration by parts formula: $\int\limits udv=uv- \int\limits vdu$

This implies that:

$\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy$

$\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}$

$I_0=\int\limits^1_0 xye^{x+y}dy$

We substitute the limits of integration and evaluate to get:

$I_0=xe^x$

This implies that:

$I=\int\limits^1_0(xe^x)dx$ .

$I=\int\limits^1_0xe^xdx$ .

We again apply integration by parts formula to get:

$\int\limits xe^xdx=e^x(x-1)$ .

$I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(0-1)$ .

$I=\int\limits^1_0xe^xdx=0-1(-1)=1$ .

No unit is given, therefore the mass of the lamina is 1.

3 0

3 years ago