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3 years ago

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Solve the equation for y. Then find the value of y for each value of x. y+5x=9;x= -2, 0, 4

1 answer:

qwelly [4]3 years ago

7 0

When x = -2

$y+5\left(-2\right)=9$

$y-5\cdot \:2=9$

$y-10=9$

$y-10+10=9+10$

$y=19$

When x= 0

$y+5\left(0\right)=9$

$y+5\cdot \:0=9$

$y+0=9$

$y=9$

When x= 4

$y+5\left(4\right)=9$

$y+5\cdot \:4=9$

$y+20=9$

$y+20-20=9-20$

$y=-11$

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B is the midpoint of AC, AB=5x and BC=2x+9 find AB,BC, and AC

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3 years ago

Read 2 more answers

If 10000 is invested at an interest rate of 10 per year ,compound semiannually,find the value of the investment after the given

slega [8]

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Part a) $\$17,958.56$

Part b) $\$32,251.00$

Part c) $\$57,918.16$

Step-by-step explanation:

<u><em>The complete question is</em></u>

If $10,000 is invested at an interest rate of 10% per year, compounded semiannually, find the value of the investment after the given number of years. (Round your answers to the nearest cent.)

a)6 years

b)12 years

c)18 years

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) 6 years

we have

$t=6\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*6}$

$A=10,000(1.05)^{12}$

$A=\$17,958.56$

Part b) 12 years

we have

$t=12\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*12}$

$A=10,000(1.05)^{24}$

$A=\$32,251.00$

Part c) 18 years

we have

$t=18\ years\\ P=\$10,000\\ r=10\%=10/100=0.10\\n=2$

substitute in the formula above

$A=10,000(1+\frac{0.10}{2})^{2*18}$

$A=10,000(1.05)^{36}$

$A=\$57,918.16$

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4 years ago